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3 years ago

Someone answer? You don’t have to answer both if you don’t know.

Chemistry

1 answer:

natima [27]3 years ago

4 0

I’m not sure what the 6 means, but for the first one, the process being shown is photosynthesis that occurs in a plant. The first two compounds are the reactants. The CO2 is carbon dioxide, and the H2O is water. When these two reactants are put together with some sunlight, they create the products. The C6H12O6 is glucose, and the O2 is oxygen.

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In which species does sulfur have the highest oxidation number? s8 (elemental form of sulfur) h2s so2 h2so3 k2so4?

Mashutka [201]

There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.

*S8. Since this is in elemental form, its oxidation number is assigned as 0.

*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.

*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.

*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.

*K₂SO₄. K is assigned with +1.
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.

<em>The S with the highest oxidation number is the one in K₂SO₄.</em>

8 0

3 years ago

Show the empirical formula manganese fluoride; 59.1% Mn and 40.9% F. Fill in the subscripts on the formula below. Make sure to h

Gre4nikov [31]

Hey there!:

Given % of Mn=59.1% means 59.1 g of Mn present in 100 g of manganese fluoride.

Molar mass of Mn= 54.938 g/mol

Moles of Mn = mass / molar mass

59.1 /54.938 => 1.07 ≈ 1 mol.

and % of F=40.9% means 40.9 g of of F present in 100 g of manganese fluoride.

Molar mass of F=18.998 g/mol

Moles of F :

40.9 / 18.999 => 2.15 mol ≈ 2 mol.

The mole ratio between Mn:F= 1 : 2

Therefore the empirical formula of manganese fluoride:

=> MnF2=Mn1F2

Hope that helps!

3 0

4 years ago

Read 2 more answers

In Period 3, from left to right in order, each successive

emmasim [6.3K]

Here are some trends you should know.
Electronegativity increases as you go right and up along the periodic table.
So, (1) is wrong
Atomic mass increases as you go right and down along the periodic table.
So, (2) is wrong
Proton number or atomic number increases as you go right and down in the table.
So, (3) is correct
Metallic character increases as you go left and down along the periodic table.
So, (4) is wrong

8 0

3 years ago

Read 2 more answers

What are some real world applications in which ph is an important factor?

Blababa [14]

Medications for skin , and medication for babies

7 0

3 years ago

The initial volume of HCl was 1.25 ml and LiOH was 2.65 ml. The final volume of HCL was 13.60 ml and LiOH was 11.20 ml. If the L

Dennis_Churaev [7]

Q1)
This is a strong acid- strong base base reaction, balanced equation for the reaction is as follows;
LiOH + HCl ---> LiCl + H₂O
stoichiometry of acid to base is 1:1
volume of HCl used up - 13.60 - 1.25 = 12.35 mL
volume of LiOH used up - 11.20 - 2.65 = 8.55 mL
molarity of LiOH - 0.140 M
The number of LiOH moles reacted - $\frac{0.140 mol/L*8.55mL}{1000mL}$ = 0.001197 mol
according to stoichiometry, number of LiOH moles = number of HCl moles
Therefore number of HCl moles reacted - 0.001197 mol
The number of HCl moles in 12.35 mL - 0.001197 mol
Then number of HCl moles in 1000 mL - $\frac{0.001197*1000mL}{12.35mL}$
Molarity of HCl - 0.0969 M

Q2)
Volume of HCl used - 12.35 mL
Volume of LiOH used - 8.55 mL
Molarity of HCl - 0.140 M
In 1 L solution of HCl there are 0.140 mol of HCl
Therefore number of HCl moles in 12.35 mL - $\frac{0.140mol*12.35 mL}{1000mL}$
Number of HCl moles reacted - 0.001729 mol
since molar ratio of acid to base is 1:1
the number of LiOH moles that reacted - 0.001729 mol
Therefore number of moles in 8.55 mL - 0.001729
Then number of LiOH moles in 1000 mL - $\frac{0.001729mol*1000mL}{8.55 mL}$
molarity of LiOH - 0.202 M

5 0

3 years ago