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Free_Kalibri [48]
3 years ago
15

What is the mass percentage of C in CH₃CH₂OH? Provide an answer to two decimal places.

Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

here's your answer

Explanation:

Molar mass of CH3CH2OH = 46.06844 g/mol

This compound is also known as Ethanol.

Convert grams CH3CH2OH to moles  or  moles CH3CH2OH to grams

Molecular weight calculation:

12.0107 + 1.00794*3 + 12.0107 + 1.00794*2 + 15.9994 + 1.00794

Percent composition by element  

Hydrogen H 1.00794 6 13.128%

Carbon C 12.0107 2 52.143%

Oxygen O 15.9994 1 34.730%

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During which two minutes time period is the temperature of water changing faster?!
Vlad1618 [11]

Answer:

2-4 minutes

Explanation:

Fastest changing temperature means larger change in temperature when subtracting final temperature from initial temperature in a given time period (given time period is 2 minutes for all the options)

For 0-2 minutes, our final temperature was 40 (at 2 min) and initial temperature was  20 (at 0 min), thus temperature change was only 20 C.

For 2-4, our final temperature was 80 (at 4 min) and initial temperature was   40 (at 2 min) thus temperature change was 40 C.

For 4-6, our final temperature was 100 (at 6 min) and initial temperature was   80 (at 4 min) thus temperature change was 20 C.

We are not given temperature at 8 min so option D is invalid.

As we can clearly see that in a given 2 minute period, option B has the fastest change because it changed 40C when compared to other options that changed only 20C from starting temperature.

Hope that makes sense.

4 0
2 years ago
Write down the different uses of water that you know about​
Yakvenalex [24]

Answer:

The various uses of water :

1. Water is used for daily purpose like cooking , bathing , cleaning and drinking.

2. Water is used as a universal solvent.

3. water maintains the temperature of our body.

4. Water helps in digestion in our body.

5 .water is used in factories and industries.

6. Water is used to grow plants , vegetables and crops.

8 0
2 years ago
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5. For the following equation:
zmey [24]

Answer:

the correct answer is option A copper and silver

4 0
3 years ago
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If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n)?
vekshin1

If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.

These consist of glycogen, cellulose, as well as starch. Benedict's reagent can be used as a test to see if there are lots of simple carbohydrates present. When it interacts with lowering sugars, it changes from turquoise to yellow or orange. These contain unbound aldehyde but rather ketone groups in simple carbohydrates.

Sugars and starches are examples of carbohydrates. They contain carbon, hydrogen, and oxygen, which appear in the ratio 1:2:1. Size-based categories for carbohydrates include monosaccharides, disaccharides, or polysaccharides. Carbohydrates act as sources of power as their main purpose.

Therefore, If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) keto pentose.

To know more about  carbohydrate

brainly.com/question/15174118

#SPJ4

4 0
1 year ago
Consider the reaction 4PH3(g) → P4(g) + 6H2(g) At a particular point during the reaction, molecular hydrogen is being formed at
Svetllana [295]

Answer:

The rate at which P_4 is being produced is 0.0228 M/s.

The rate at which PH_3 is being consumed is 0.0912 M/s.

Explanation:

4PH_3\rightarrow P_4(g)+6H_2(g)

Rate of the reaction : R

R=\frac{-1}{4}\frac{d[PH_3]}{dt}=\frac{1}{6}\frac{d[H_2]}{dt}=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which hydrogen is being formed = \frac{d[H_2]}{dt}=0.137 M/s

R=\frac{1}{6}\frac{d[H_2]}{dt}

R=\frac{1}{6}\times 0.137 M/s=0.0228 M/s

The rate at which P_4 is being produced:

R=\frac{1}{1}\frac{d[P_4]}{dt}

0.0228 M/s=\frac{1}{1}\frac{d[P_4]}{dt}

The rate at which PH_3 is being consumed :

R=\frac{-1}{4}\frac{d[PH_3]}{dt}

0.0228 M/s\times 4=\frac{-1}{1}\frac{d[PH_3]}{dt}

\frac{-1}{1}\frac{d[PH_3]}{dt}=0.912 M/s

6 0
3 years ago
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