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Salsk061 [2.6K]
3 years ago
11

Friction depends on the types of surfaces involved and how hard the surfaces push together.

Chemistry
2 answers:
skad [1K]3 years ago
6 0
True, if you have rough surface the more friction you have. The More slipery, less friction.
bearhunter [10]3 years ago
5 0
<span>True.....................</span>
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Which DSS principle determines solutions or alternate actions in precision farming
lidiya [134]
When multiple data streams are collected, one must decide how those data will be fused in the decision process. Separate data streams can be:

Mixed mode (including both quantitative and qualitative data).
Redundant (validating the data from another stream).
Complementary (providing measures of multiple characteristics of an object).
Supportive (helping verify some interpretation of another data stream).
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3 years ago
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Using Newton's Law of Inertia, explain the purpose of a headrest in a vehicle.
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In a forward collision, the driver and everyone else's head is thrusted back (because the energy transfer from one car to another [i.e. the Inertia] ).. the head rest is there to stop the heads from moving to far back that it could break your neck.
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4 years ago
Why is the mixture of the titration of potassium permanganate solution using oxalic acid heated before titration? ​
alexgriva [62]

Explanation:

During titration of oxalic acid and KMnO_4 in acid medium to reaction is extremely slow. SinceKMnO_4 is acting as a self indicator the colour disappears after less than 30s even after approaching equivalent point. So the reaction mixture is heated to approximately 70–80^0 C (just before it starts boiling) and the titration is started. This helps in initiating the reaction via supplying the necessary activation energy of the reaction.  Secondly the heat helps to decompose [Mn(C_2O_4)^3]^{-3}complex which forms as a result of local excess of KMnO_4.the complex is unstable above 60^0C and the Mn^{+2} formed as a result catalyses the rest of the reaction. Thirdly the temp should never exceed the range given as oxalic acid will decompose above this temp to Co_2

4 0
4 years ago
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Equal masses (in grams) of hydrogen gas and oxygen gas are reacted to form water. Which substance is limiting?
Sonbull [250]

Answer:

a. Oxygen gas is limiting

Explanation:

hydrogen gas and oxygen gas are reacted to form water

2H₂ + O₂  →  2H₂O

the above balanced equation shows that 2 moles of H₂ is required for 1 mole of O₂

Given equal masses of H₂ and O₂

assuming 'x' gm for each, no. of moles of each gas  =

no. of moles of H₂ = x/2 = 0.5x moles

no.of moles of O₂ = x/32 = 0.031x moles

This shows that no. of moles of O₂ is very less so O₂ will become the limiting reagent.

3 0
4 years ago
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The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r
rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

    = 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0
3 years ago
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