817.567 mm hg the answer for number 2
There are two types of 'quantities' namely: scalar and vector
A 'vector' is a quantity that has both magnitude and direction whereas a 'scalar' has only magnitude.
Magnitude is a measure or the size of the quantity or object.
In the given example of the vector: '75 mph to the north'
Magnitude is the number 75 mph
Direction is north
Ans C)
Answer:
The amount of calcium carbonate will increase.
Explanation:
K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.
- K>Q , reaction will move forward by making more product.
- K<Q , reaction will move backward by making more reactant.
Equilibrium constant of the reaction = 
Concentration of 
Concentration of 
Concentration of 
![Q=\frac{[CaO][CO_2]}{[CaCO_3]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BCaO%5D%5BCO_2%5D%7D%7B%5BCaCO_3%5D%7D)
This means that equilibrium will move in backward direction by which amount of calcium carbonate will increase.
Answer:
Ksp = 2.4 * 10^-13
Explanation:
Step 1: Data given
Molarity of NaIO3 = 0.10 M
The molar solubility of Pb(IO3)2 = 2.4 * 10^-11 mol/L
Step 2: The initial concentration
NaIO3 = 0.1M
Na+ = 0 M
2IO3- = 0 M
Step 3: The concentration at the equilibrium
All of the NaIO3 will react (0.1M)
At the equilibrium the concentration of NaIO3 = 0 M
The mol ratio is 1:1:1
The concentration of Na+ and IO3- is 0.1 M
Pb(IO3)2 → Pb^2+ + 2IO3^-
The concentration of Pb(IO3)2 can be written as X
The concentration of Pb^2+ can be written as X
The concentration of 2IO3^- can be written as 2X
Ksp = (Pb^2+)(IO3^-)²
⇒ with (Pb^2+) = 2.4*10^-11
⇒ with (IO3^-) = 2x from the Pb(IO3)2 and 0.1M from the NaIO3.
⇒The total (IO3^-) = 2x + 0.1 and we assume that x is so small that we can neglect it.
Ksp = (2.4 *10^-11)*(0.1)²
Ksp = 2.4 * 10^-13
In 5.2 moles of C7H18 there are 7*5.2 moles of carbon which is 36.4.
This is because for every molecule C7H18 there will always be 7 carbons.
Remember that a mole is just a way of quantifying stuff
So if we have 6.02*10^23 molecules, we will have 7*6.02*10^23 carbon atoms.
Therefore, we just have the number of molecules in a different unit, the mole so its still 7 times greater.
Another example would be that there is 5.2*18 = 93.6 moles of H since there is 18 atoms of hydrogen per molecule of C7H18.
