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N76 [4]
2 years ago
15

Changing subscripts is one of the steps of balancing a chemical equation. True or False

Chemistry
2 answers:
VladimirAG [237]2 years ago
8 0
The answer is false
have a good night !!!
Lostsunrise [7]2 years ago
3 0

Answer:

False

Explanation:

Changing the coefficients is one of the steps of balancing a chemical equation. Changing the subscript changes the compounds being used, while changing the coefficient changes the amount of each compound being used.

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109kPa = _________ mm Hg
LekaFEV [45]

817.567 mm hg the answer for number 2

3 0
3 years ago
What is the magnitude of the vector described below?
photoshop1234 [79]

There are two types of 'quantities' namely: scalar and vector

A 'vector' is a quantity that has both magnitude and direction whereas a 'scalar' has only magnitude.

Magnitude is a measure or the size of the quantity or object.

In the given example of the vector: '75 mph to the north'

Magnitude is the number 75 mph

Direction is north

Ans C)

3 0
3 years ago
Read 2 more answers
At 1173 K, Keq = 0.0108 for the following reaction: CaCO3(s) ⇄ CaO(s) + CO2(g) The reaction takes place in a 10.0 L vessel at 11
maxonik [38]

Answer:

The amount of calcium carbonate will increase.

Explanation:

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

  • K>Q , reaction will move forward by making more product.
  • K<Q , reaction will move backward by making more reactant.

CaCO_3(s)\rightleftharpoons CaO(s) + CO_2(g)

Equilibrium constant of the reaction = K_{eq}=0.0108

Concentration of CaO=\frac{15.0 g}{56 g/mol\times 10.0L}=0.027 M

Concentration of CO_2=\frac{4.25 g}{44 g/mol\times 10.0L}=0.0096 M

Concentration of CaCO_3=\frac{15.0 g}{100 g/mol\times 10.0L}=0.015 M

Q=\frac{[CaO][CO_2]}{[CaCO_3]}

=\frac{0.027 mol/L\times 0.0096 mol/L}{0.015 mol/L}=0.0174

K_{eq}

This means that equilibrium will move in backward direction by which amount of calcium carbonate will increase.

4 0
3 years ago
The molar solubility if Pb(IO3)2 in
lana66690 [7]

Answer:

Ksp = 2.4 * 10^-13

Explanation:

Step 1: Data given

Molarity of NaIO3 = 0.10 M

The molar solubility of Pb(IO3)2 = 2.4 * 10^-11 mol/L

Step 2: The initial concentration

NaIO3 = 0.1M

Na+ = 0 M

2IO3- = 0 M

Step 3: The concentration at the equilibrium

All of the NaIO3 will react (0.1M)

At the equilibrium the concentration of NaIO3 = 0 M

The mol ratio is 1:1:1

The concentration of Na+ and IO3- is 0.1 M

Pb(IO3)2 → Pb^2+ + 2IO3^-

The concentration of Pb(IO3)2 can be written as X

The concentration of Pb^2+ can be written as X

The concentration of 2IO3^- can be written as 2X

Ksp = (Pb^2+)(IO3^-)²

⇒ with (Pb^2+) = 2.4*10^-11

 ⇒ with (IO3^-) = 2x from the Pb(IO3)2 and 0.1M from the NaIO3.

   ⇒The total (IO3^-) = 2x + 0.1 and we assume that x is so small that we can neglect it.

Ksp = (2.4 *10^-11)*(0.1)²

Ksp = 2.4 * 10^-13

7 0
3 years ago
How many moles of carbon are in 5.2 moles of C7H18
Iteru [2.4K]
In 5.2 moles of C7H18 there are 7*5.2 moles of carbon which is 36.4.

This is because for every molecule C7H18 there will always be 7 carbons.

Remember that a mole is just a way of quantifying stuff

So if we have 6.02*10^23 molecules, we will have 7*6.02*10^23 carbon atoms.

Therefore, we just have the number of molecules in a different unit, the mole so its still 7 times greater. 

Another example would be that there is 5.2*18 = 93.6 moles of H since there is 18 atoms of hydrogen per molecule of C7H18.


4 0
3 years ago
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