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4 years ago

Which statements describe the genetic code? Check all that apply.

Chemistry

2 answers:

Rashid [163]4 years ago

7 0

Answer:

B,C, and D are the answers.

Explanation:

g100num [7]4 years ago

4 0

B.) It is a nucleic acid.
C.) It is found in DNA.
E.) It is used to build an organism’s structures.
F.) It allows parents and their young to have similar characteristics.

Hope this helps!

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An ecologist studies the relationships among organisms. The work of an ecologist will most likely help solve problems related to

Lerok [7]

Answer: The protection of the environment.

Explanation: An ecologist refers to an individual who handles the ecosystem and its constituents to perform surveys and evaluate the behavior and diversity of various species. They examine the association between the surrounding and its living things. They work for environmental consulting agencies, NGOs, and the government, and helps them in doing research and creating protocols and rules for the protection of the environment.

6 0

3 years ago

For each of the following, use the periodic table to determine the number of valence electrons in an atom of the element.

Kipish [7]

Explanation:

Ne 8. S 6. Mg 2. Sn 4. C 4. Al 3. Te 6. Cs 1. Bi 5. Br 7. Ga 3. P 5.

5 0

3 years ago

A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of

andrew-mc [135]

Answer: The molecular formula for the given organic compound X is $C_6H_{8}O_7$

Explanation:

We are given:

Mass of $CO_2=4.13g$

Mass of $H_2O=1.13g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, = $\frac{12}{44}\times 4.13=1.13g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, $\frac{2}{18}\times 1.13=0.125g$ of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = $\frac{0.094}{0.094}=1$

For Hydrogen = $\frac{0.125}{0.094}=1.33$

For Oxygen = $\frac{0.109}{0.094}=1.16$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is $C_6H_8O_7$

Empirical mass = $6\times 12+8\times 1+7\times 16=192g$

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

Putting values in above equation, we get:

$n=\frac{192g/mol}{192g/mol}=1$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_6H_8O_7\times 1=C_6H_{8}O_7$

Thus molecular formula for the given organic compound X is $C_6H_{8}O_7$

7 0

3 years ago

What would carbon and chlorine form if they bond

olganol [36]

That is a bond between carbon and chlorine, as in chloro methane:

H3C-cl
i hope i helped you❤

5 0

4 years ago

Refer to the reaction between magnesium and oxygen In the introduction. What elements is oxidizing?write the oxidation number fo

erica [24]

Answer:

Oxidizing element: Mg

Explanation:

Reaction of magnesium and oxygen can be written as:

$2Mg +O_2 \rightarrow 2MgO$

while writting chemical reaction between two atom or element then write their natural form i.e. how that atom or element exist in the nature.

eg. reaction of any element with Oxygen atom then we can not write directly O because oxygen exist in the nature in form of $O_2$

finding oxidation number each side:

Reactant side:

Mg=0;

O=0;

product side:

Mg=+2;

O=-2;

from above:

oxidation number of Mg is increasing hence this is oxidizing element

7 0

3 years ago