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SCORPION-xisa [38]
3 years ago
11

How many moles are contained in 2.3 liters of a 1.2M solution?

Chemistry
1 answer:
elena-s [515]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 2.76 \ mol}}

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

molarity = \frac {moles}{liters}

We know the molarity is 1.2 M (mol\liter) and there are 2.3 liters of solution. Substitute the known values into the formula.

1.2 \ mol/liter= \frac {x}{2.3 \ liters}

Since we are solving for x, we must isolate the variable. It is being divided by 2.3 and the inverse of division is multiplication. Multiply both sides by 2.3 liters.

2.3 \ liters *1.2 \ mol/liter= \frac {x}{2.3 \ liters}* 2.3 \ liters\\2.3 *1.2 \ mol= x\\2.76 \ mol =x

In a solution with a molarity of 1.2 and 2.3 liters of solution, there are 2.76 moles.

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5 0
2 years ago
Assume that the rate law for a generic chemical reaction is rate = [a][b]3 . what is the reaction order in a, the reaction order
SIZIF [17.4K]
If the reaction is
     X + Y → Products

Then the rate is
     R = k[X]ᵃ [Y]ᵇ

Where,
R = the rate of the reaction (mol L⁻¹ s⁻¹)
k = rate constant
[X] and [Y] = concentrations of the reactants (mol L⁻¹)
a = order of the reaction with respect to X
b = order of the reaction with respect to Y
overall reaction order, n = a + b

according to the given rate expression,
rate = [a][b]³

order of the reaction with respect to 'a' is 1
order of the reaction with respect to 'b' is 3

Overall reaction order = 1 + 3
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8 0
3 years ago
From the enthalpies of reaction H2(g)+F2(g)→2HF(g)ΔH=−537kJ C(s)+2F2(g)→CF4(g)ΔH=−680kJ 2C(s)+2H2(g)→C2H4(g)ΔH=+52.3kJ calculate
DIA [1.3K]

Answer:

\Delta H for the given reaction is -2486.3 kJ

Explanation:

The given equation can be written as a combination of the following equation:

2H_{2}(g)+2F_{2}(g)\rightarrow 4HF(g)  ; \Delta H_{1}= (2\times -537kJ)=-1074 kJ

2C(s)+4F_{2}(g)\rightarrow 2CF_{4}(g)  ;  \Delta H_{2}=(2\times -680kJ)=-1360kJ

C_{2}H_{4}(g)\rightarrow 2C(s)+2H_{2}(g)  ;  \Delta H_{3}=-52.3kJ

-----------------------------------------------------------------------------------

C_{2}H_{4}(g)+6F_{2}(g)\rightarrow 2CF_{4}(g)+4HF(g)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=(-1074-1360-52.3)kJ=-2486.3kJ

6 0
3 years ago
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Answer:

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Explanation:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

For example, when wood burns, the mass of the soot, ashes, and gases equals the original mass of the charcoal and the oxygen when it first reacted. So the mass of the product equals the mass of the reactant.

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2 years ago
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