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Brut [27]
3 years ago
13

Methanol (ch3oh) can be made by the reaction of co with h2: co(g)+2h2(g)⇌ch3oh(g) to maximize the equilibrium yield of methanol,

would you use a high or low temperature?
Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
8 0
The enthalpy of the creation of Methanol is negative. This means heat is released when the reaction proceeds. You would want to use a low temperature.
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^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}

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<h3>Explanation </h3>

^{222}_{\phantom{2}86}\text{Rn} \to ^{A}_{Z}\text{Y}+ ^{4}_{2}\text{He}

Here's the symbol of a particle in a nuclear reaction. ^{A}_{Z}\text{Y}.

A stands for mass number. Z stands for atomic number. Both numbers shall conserve in a nuclear reaction.

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So is the case for the atomic number. Try figure out the atomic number of Y using the same approach.

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What element is Y? The atomic number of Y is 84. Refer to a periodic table. Element 84 corresponds to Po (polonium). Y is Polonium-218. The symbol of Y should be written as ^{218}_{\phantom{2}84}\text{Po}. Hence the equation:

^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}.

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