Assume it is 1 litre and weighs 1kg.
2 percent of 1 kg is 20g.
20g divided by molar mass of NaOH.
20g divide by 40 = 0.5 mole
0.5 mole in a litre would be 0.5M
That is the answer: 0.5M
%Mass
Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

or

CH4 + 2O2 =======> CO2 + 2H2O
Anode- oxidization
Cathode-reduction
Answer:
Explanation:
The actual boiling point is probably between 34C and 40C.