Answer:
Explanation:
Hello,
In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:
By knowing the volume and the concentration of the NaOH, one obtains:
Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:
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Answer:
80.1 grams
Explanation:
Find the molar mass of CH3OH first by using the periodic table values.
12.011 g/mol C + (1.008*3 g/mol H) + 15.999g/mol O + 1.008 g/mol H
=32.042 so that is the molar mass
Now that you have 2.50 moles of CH3OH, you can calculate the mass in g
2.50molCH3OH * (32.042g CH3OH / 1 mol CH3OH) = 80.105
32.042g / 1 mol is the same as 32.042 g/mol
Since there are 3 sig figs in the problem (2.50 has 3 sig figs), you round to 80.1 g CH3OH
Answer:
I think it both physical & chemical change :')
The answer is A. 0 because 9 and 14 would be a pH of basic solutions because they are greater than 7; 0 and 6 are acidic because they are less than 7 but zero is smaller than 6 so it is the most acidic
Answer:
Explanation:
Hello!
In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:
Thus, the percent water is:
So we plug in to obtain:
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