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ryzh [129]
3 years ago
8

Which of these formulas contain equal numbers of nitrogen atoms?

Chemistry
2 answers:
Vesnalui [34]3 years ago
7 0

AAnswer:

Explanation:

Because it’s right

marishachu [46]3 years ago
7 0

Answer:

Its D

Explanation:

Because 1 nitrogen atom is N2 and theres an N2 in all of those

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Water from a riverbed carries sediment downstream. The water pressure cuts deep into the riverbed, creating a deep, narrow chann
atroni [7]

Answer:

A canyon has formed.

Explanation:

5 0
2 years ago
Refer to the example about diatomic gases A and B in the text to do problems 19 - 27.
soldier1979 [14.2K]

Answer:a

Explanation:

5 0
3 years ago
A 30.5 g sample of an alloy at 95.0°C is placed into 49.3 g water at 24.3°C in an insulated coffee cup. The heat capacity of the
user100 [1]

Answer:

0.752 J/g*K

Explanation:

The heat lost by the alloy (which is negative) must be equal to the heat gained by the water and the coffee cup:

-Qa = Qw + Qc

-ma*ca*ΔTa = mw*cw*ΔTw + C*ΔTc

Where, m is the mass, c is the specific heat capacity, C is the heat capacity of the coffee cup, ΔT is the change in temperature, a represents the alloy, and w the water.

The coffee cup has initial temperature equal to the water, then:

-30.5*ca*(31.1 - 95.0) = 49.3*4.184*(31.1 - 24.3) + 9.2*(31.1 - 24.3)

1948.95ca = 1465.20

ca = 0.752 J/g*K

4 0
3 years ago
How many moles in 3.69 x 10^30 molecules of carbon dioxide?
Sedaia [141]

0.612 \times 10^{7} \text { moles of } \mathrm{CO}_{2} are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}

<u>Explanation:</u>

It is known that each mole of an element is composed of avagadro's number of molecules. So if we need to determine, we need to divide the number of molecules with the avagadro's number.

So,

    1 mol of element =6.02 \times 10^{23} molecules of element

As here 3.69 \times 10^{30} molecules of carbon di oxide is given. So the moles in it will be

   No. of moles of carbon dioxide = \frac{3.69 \times 10^{30}}{6.02 \times 10^{23}}

    No. of moles = 0.612 \times 10^{7} moles of carbon dioxide.

Thus,

0.612 \times 10^{7} of carbon dioxide are present in 3.69 \times 10^{30} \text { molecules of } \mathrm{CO}_{2}.

4 0
3 years ago
Please help! ill give you 90 points!
Luba_88 [7]

Answer:

1.d = 2.70 g/mL

2.d = 13.6 g/mL

4.d = 1896 g / 212.52 cm3 = 8.9 g/cm3

Explanation:If this helped subscribe to Amiredagoat Yt

3 0
3 years ago
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