Answer:
By increasing the pressure, the molar concentration of N2O4 will increase
Explanation:
We have the equation 2NO2 ⇔ N2O4
This equation is reversible and exotherm. By <u>decreasing the temperature</u>, the reaction will produce more energy, so the reaction will move to the right. But a lower temperature also lowers the rate of the process, so, the temperature is set at a compromise value that allows N2O4 to be made at a reasonable rate with an equilibrium concentration that is not too unfavorable
So <u>increasing the temperature</u> will shift the equilibrium to the left. The equilibrium shifts in the direction that consumes energy.
If we d<u>ecrease the concentration of NO2</u>, the equilibrium will shift to the left, resulting in forming more reactants.
To increase the molar concentration of the product N2O4, we have to <u>increase the pressure</u> of the system.
NO2 takes up more space than N2O4, so increasing the pressure would allow the reactant to collide more form more product.
By increasing the pressure, the molar concentration of N2O4 will increase
Answer:
Answer: The correct answer is Option B.
Explanation:
To calculate the number of moles, we use the equation:
\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}Number of moles=Molar massGiven mass ....(1)
For N_2N2 :
Given mass of nitrogen gas = 10 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in above equation, we get:
\text{Moles of iron oxide}=\frac{10g}{28g/mol}=0.357molMoles of iron oxide=28g/mol10g=0.357mol
The given chemical reaction follows:
N_2+O_2\rightarrow 2NON2+O2→2NO
As, oxygen gas is present in excess. Thus, it is considered as an excess reagent and nitrogen is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
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Answer:
Explanation:
Hello,
In this case, we find the following states:
a. Liquid salt water at 28.0 °C.
b. Liquid salt water at 102.5 °C.
c. Vapor salt water at 102.5 °C.
The first process (1) is to heat the liquid water from 28.0 °C to 102.5 °C and the second one (2) to vaporize the liquid salt water. In such a way, each process has an amount of energy that when added, yields the total energy for the process as shown below:
Best regards.
The correct answer is 230 mmHg.
When liquid water boils at 100°C, the water vapor pressure is 760 mmHg
Hence, when liquid water boils at 50°C, the water vapor pressure is (760/2) mmHg or 230 mm Hg.
As the boiling temperature of water halves so does the vapor pressure of water. This is in accordance to Pressure Law.
According to Pressure law, pressure is directly proportional to the absolute temperature, at constant volume.