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MAXImum [283]
3 years ago
13

What is 50m as a percentage of 5km

Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0

50m as a percentage of 5km is 1%.

50m in meters is 50

5km in meters is 5000

50m is 1% of 5000m

I hope this has helped you. :)

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What is the gcf of 3/7 and 4/9?
LiRa [457]

Answer:

  1/63

Step-by-step explanation:

There are a couple of ways to do this.

<h3>1) </h3>

Look for the GCF of the numerators when a common denominator is used.

  GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)

  GCF(3/7, 4/9) = 1/63

__

<h3>2) </h3>

Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.

  (4/9)/(3/7) = 1 remainder 1/63*

  (3/7)/(1/63) = 27 remainder 0

The GCF is 1/63.

__

* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.

_____

<em>Additional comment</em>

3/7 = (1/63) × 27

4/9 = (1/63) × 28

3 0
3 years ago
Question 10 (10 points)
Verdich [7]

Answer: $-84

Step-by-step explanation:

4 0
3 years ago
A point is in a circle if the distance from the center of the circle to the point is equal to the
notka56 [123]
The answer is the Radius.
3 0
3 years ago
Read 2 more answers
The average weight of 3 containers A,B and C is 3.2kg. Container A is twice as heavy as container B. Containers B is 400 g heavi
dlinn [17]

Answer:

The weight of container C is 2.1kg.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the weight of container A.

y is the weight of container B.

z is the weight of container C.

The average weight of 3 containers A,B and C is 3.2kg.

This means that the total weight is 3*3.2 = 9.6kg. So

x + y + z = 9.6

Container A is twice as heavy as container B.

This means that x = 2y.

Containers B is 400 g heavier than container C.

400g is 0.4kg. So

This means that y = z + 0.4, or z = y - 0.4

Replacing y and z as functions of x in the first equation:

x + y + z = 9.6

2y + y + y - 0.4 = 9.6

4y = 10

y = \frac{10}{4} = 2.5

Container C

z = y - 0.4 = 2.5 - 0.4 = 2.1

The weight of container C is 2.1kg.

4 0
3 years ago
If
Elena L [17]

Evaluate the derivative of f(x) at x = 1. I'll use the limit definition:

\displaystyle \lim_{x\to1} \frac{f(x)-f(1)}{x-1} = \lim_{x\to1} \frac{6x^2-x^3-5}{x-1} = \lim_{x\to1}(-x^2+5x+5) = 9

Then using the point-slope formula, the equation of the tangent line to f(x) at the point (1, 5) is

y - 5 = 9 (x - 1)

y = 9x - 4

3 0
3 years ago
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