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KiRa [710]
4 years ago
12

A solution to an equation is a number when substituted back into the original equation produces a what statement

Mathematics
1 answer:
sergij07 [2.7K]4 years ago
6 0

Answer:

true statement

Step-by-step explanation:

Substituting a solution back into the original equation will make the equation true.


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PLEAASSEEE HELP ASAP!!!​
eduard

Answer:

= 2 \frac{7}{23}  \\  \\

Step-by-step explanation:

5 \frac{3}{8}  - 3 \frac{1}{6}  \\  \\  \frac{43}{8}  -  \frac{19}{6}  \\  \\  \frac{258 - 152}{48}  \\  \\  \frac{106}{48}  \\  \\  \frac{53}{23}  = \:  \:  2 \frac{7}{23}

8 0
4 years ago
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Can pretty please help me with 2 math question its due today
Mashcka [7]
Answer:
(4x + 12 ) - ( -8 ) =
4x + 20
Explanation:
Just add them up and form a equation ( this is for the second one )
5 0
3 years ago
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Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
Quick! Andrew has to play 15 games in a chess tournament. At some point during the tournament he has won half of the games he ha
nikklg [1K]

x - the number of the games he played

\dfrac{x}{2} - the number of the games he won

\dfrac{x}{3} - the number of the games he lost

x=\dfrac{x}{2}+\dfrac{x}{3}+2\Big|\cdot6\\6x=3x+2x+12\\x=12

15-12=3

<u>so, he has still 3 games to play</u>

3 0
3 years ago
Let A and B are n x n matrices from which A is invertible. Suppose AB is singular. What conclusion can be made about the inverti
Montano1993 [528]

Answer: Matrix B is non- invertible.

Step-by-step explanation:

A matrix is said to be be singular is its determinant is zero,

We know that if a matrix is singular then it is not invertible.    (1)

Or if a matrix is invertible then it should be non-singular matrix.      (2)

Given :  A and B are n x n matrices from which A is invertible.

Then A must be non-singular matrix.                            ( from 2 )

If AB is singular.

Then either A is singular or B is singular but A is a non-singular matrix.

Then , matrix B should be a singular matrix.                   ( from 2 )

So Matrix B is non- invertible.                                     ( from 1 )

7 0
3 years ago
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