Answer:
The length of the rectangular park is 
and the width of the rectangular park is 
Step-by-step explanation:
Let
x ----> the length of the rectangular park
y ---> the width of the rectangular park
we know that
The perimeter is equal to
so
-----> equation A
----> equation B
substitute equation B in equation A and solve for y
Find the value of x
therefore
The length of the rectangular park is and the width of the rectangular park is
When you read this, the first thing that should jump out at you is:
What does "largest" mean ?
Does it mean the longest possible playground ? The widest possible ?
The playground with the most possible area ?
Well, we can narrow it down right away. If you try and find the longest
or the widest possible playground, then what you get is: The longest or
the widest possible playground is 250 feet by zero. It has a perimeter
of 500 ft, and nobody can play in it. That's silly.
It makes a lot more sense if we look for the playground that has
the greatest AREA.
I happen to remember that if you have a certain fixed amount of
fence and you want to use it to enclose the most possible area,
then you should form it into a circle. And if it has to be a rectangle,
then the next most area will be enclosed when you form it into a square.
So you want to take your 500 feet of fence and make a playground
that's 125-ft long and 125-ft wide.
Its area is (125-ft x 125-ft) = 15,625 square feet.
Just to make sure that a square is the right answer, let's test
what we would have if we made it not quite square ... let's say
1 foot longer and 1 foot narrower:
Length = 126 feet
Width = 124 feet
Perimeter = 2 (126 + 124) = 500-ft good
Area = (126-ft x 124-ft) = 15,624 square feet.
Do you see what happened ? We kept the same perimeter, but
as soon as we started to make it not-square, the area started to
decrease.
The square is the rectangle with the most possible area.
The answer is 10 radical 11
