All categories

2 years ago

Find the area of the figure.

Mathematics

1 answer:

konstantin123 [22]2 years ago

4 0

Answer:

132

Explanation:

All you need to do is separately find the area of the shapes that are part of the figure (in this case the trapezoid and rectangle), and then add them all up.

1.(7x4) + (1/2x8[7+19])

2. 28 + 104

3. 132

~Hope this helps you~

You might be interested in

A measure of three angles of a triangle is shown below. What is the measurement of x? Record your answer in the gridable below.

Kaylis [27]

x + (x + 2) + 38 = 180

2x + 40 = 180

2x = 140

x = 70

6 0

2 years ago

How much water and how much drink mix should Jerome use to make enough energy drink for all the runners? Create a table to show

yanalaym [24]

Answer: First, you need to figure out 22 times 2 = 44. Then, you need to multiply the original ratio by 44 to get the answer.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

14. What is the reflection image of (5, -3) across the line y = -x? (3, -5) (3, 5) (-3, 5) (-3, -5)

Nata [24]

Answer:

The reflection image of (5, -3) across the line y = -x is (3, -5).

Step-by-step explanation:

You can find the reflection equation by putting the value of x and y in the line given one by one.

5 0

3 years ago

Please help me out with this problem!

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

The red graph is the graph of y = f(x) shifted 1 unit right and then reflected in the x- axis.

Given y = f(x) then f(x + a) is a horizontal translation of a units

• If a > 0 then shift to the left of a units

• If a < 0 then shift to the right of a units

Here shift to the right of 1 unit, thus

y = f(x - 1)

Under a reflection in the x- axis

a point (x, y ) → (x, - y )

Note the y- coordinates are the negative of each other, thus

- y = f(x)

Now $\frac{y}{-1}$ = - y, hence

The equation for the red graph is

$\frac{y}{-1}$ = f(x - 1) → C

6 0

2 years ago

Can you please help me?

zubka84 [21]

So the right answer is 9

Look at the attached picture

Hope it will help you...

Good luck on your assignment

3 0

3 years ago