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leonid [27]
3 years ago
11

Find the area of the figure.

Mathematics
1 answer:
konstantin123 [22]3 years ago
4 0

Answer:

<em>132</em>

<em />

Explanation:

All you need to do is separately find the area of the shapes that are part of the figure (in this case the trapezoid and rectangle), and then add them all up.

1.(7x4) + (1/2x8[7+19])

2. 28 + 104

3. 132

~Hope this helps you~

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PLEASE HELP ME SOLVE FOR X
jeka57 [31]

Looks like the labeled angle is bisected, in which case we can apply the angle bisector theorem. For this triangle, it says

\dfrac x3=\dfrac{x+2}{x+4}

Solve for x:

x(x+4)=3(x+2)

x^2+4x=3x+6

x^2+x-6=0

(x+3)(x-2)=0

Then either x=-3 or x=2, but since x is a length, it must be positive. So <em>x</em> = 2.

8 0
3 years ago
6th grade math help me please !
antiseptic1488 [7]

First we have to figure out how much 3 bags cost using the total cost of $8.25

That means. we would do 8.25/3 and 8.25 divide by 3 equals 2.75.

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6 0
3 years ago
Please help due in 10 min.
sleet_krkn [62]

Answer:

A: equiangular   S: Right

Step-by-step explanation:

5 0
3 years ago
In ΔSTU, the measure of ∠U=90°, ST = 9.7 feet, and US = 4 feet. Find the measure of ∠T to the nearest degree.
BaLLatris [955]

Answer:

Around 24 degrees

Step-by-step explanation:

*Make sure calculator is on degree mode*

Try to draw out triangle--it helps

Need to use law of sines... this is where an angle and the side that opposes it are equal to each other. For example, Angle U is equal to 9.7

\frac{sin\alpha }{4} = \frac{sin90}{9.7}

Multiply 4 and sin90 and then divide the product by 9.7

Use sin^{-1} on calculator to convert the answer into degrees

5 0
3 years ago
PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
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