Answer:
Step-by-step explanation:
If you plot J and K in a coordinate plane, you see that the line formed is a perfectly horizontal line through y = 2. In order for this triangle to be an isosceles, the third x-coordinate would have to be located midway through the x-coordinates of the base. The midpoint between the x-coordinates is found by adding the 2 x-coordinates and dividing the sum by 2. -6+\3 = -3 and -3/2 = -3/2. So the x-coordinate is -3.2 or -1.5
Answer:
<h3>
f(x) = - 3(x + 8)² + 2</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the quadratic function with vertex (h, k)
the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8
the <u>maximum height of 2</u> means k = 2
So:
f(x) = a(x - (-8))² + 2
f(x) = a(x + 8)² + 2 - the vertex form of the quadratic function with vertex (-8, 2)
The parabola passing through the point (-7, -1) means that if x = -7 then f(x) = -1
so:
-1 = a(-7 + 8)² + 2
-1 -2 = a(1)² + 2 -2
-3 = a
Threfore:
The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:
<u>f(x) = -3(x + 8)² + 2</u>
Answer: $3,166
Step-by-step explanation:
Remember
if ab=0, then assume that a and b equal 0
factor out common term
comon term in 6x^2 and 15x is 3x
3x(2x)+3x(5)=0
3x(2x+5)=0
set each to zero
3x=0
x=0
2x+5=0
2x=-5
x=-5/2
x=-5/2 and 0
