Someone help please and make sure the answer is right plz :)

Mathematics

2 answers:

IgorC [24]2 years ago

8 0

The angles are corresponding, and the lines are parallel. This means the angles are equal. What can you add to 53 to get 50°? -3.

solong [7]2 years ago

4 0

The answer is -3 bc -3 + 53 = 50

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Yertle the turtle and his 362 turtle buddies went swimming in 3 different ponds. if the same number of turtles swim in each pond

konstantin123 [22]

There are 363 turtles (including yertle)
there are 3 different ponds and the same # in each pond. you simply divide the number of turtles by 3 because there are 3 different ponds.

363/3=121
there 121 turtles in each pond

8 0

2 years ago

???? I’m very confused

Liono4ka [1.6K]

C; 120 because 24x=360 so x=15. Then ABC is 8x, so 8*15=120.

8 0

3 years ago

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$