Does anyone know how to solve this?

Mathematics

1 answer:

Rzqust [24]3 years ago

8 0

John used the ginger because he used the second least amount

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Marion bought 14 packages of plastic frog and lizard fishing lures. She bought frog lures in packages of 4 and lizard lures in p

tatuchka [14]

Answer:

Marion bought 6 frog lures and 8 lizard fishing lures.

Step-by-step explanation:

Let $f$ represent frog lures and $l$ represent lizard lures.

The total packages Marion bought is

$f+l=14...eqn1$

If she bought frog lures in packages of 4 and lizard lures in packages of 6 for a total of 72 lures, then

$4f+6l=72...eqn2$

We make $f$ the subject in equation 1 and put it into equation 2 to get;

$f=14-l...eqn3$

We put equation 3 into equation 2 to get;

$4(14-l)+6l=72$

$\Righttarrow 2(14-l)+3l=36$

We expand the bracket to get;

$28-2l+3l=36$

$-2l+3l=36-28$

$l=8$

We put $l=8$ into equation 3 to get;

$f=14-8$

$f=6$

Therefore Marion bought 6 frog lures and 8 lizard fishing lures.

6 0

2 years ago

What is the oblique asymptote of the function f(x) x^2+x-2/x+1

Mamont248 [21]

$f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}
$

$\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
=0$

Consequently, t<span>he limit of $f(x)$ as x approaches infinity is $x$ .

In other words, $f(x)$ approaches the line y=x,
</span><span>
so oblique asymptote is y=x.

I'm Japanese, if you find some mistakes in my English, please let me know.</span>