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goldenfox [79]
3 years ago
6

Does anyone know how to solve this?

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0
John used the ginger because he used the second least amount
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This photo is the explanation

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2 years ago
How do i solve 1/4 +1/3​
mojhsa [17]

Answer:

\large\boxed{\dfrac{1}{4}+\dfrac{1}{3}=\dfrac{7}{12}}

Step-by-step explanation:

\dfrac{1}{4}+\dfrac{1}{3}\qquad\text{find}\ LCD=(4)(3)=12\\\\=\dfrac{1\cdot3}{4\cdot3}+\dfrac{1\cdot4}{3\cdot4}=\dfrac{3}{12}+\dfrac{4}{12}=\dfrac{3+4}{12}=\dfrac{7}{12}

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2 years ago
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there is a direct path from gayle's house to the store. due to construction, the direct route is closed and gayle must travel 6
NikAS [45]

Answer:

c2=10

Step-by-step explanation:

8^2+6^2=c2

64+36=120

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4 0
2 years ago
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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
4(a + 2) = -4<br> whats A
OLga [1]
The answer is -3 because -3+2=-1 then -1(4)=-4
4 0
3 years ago
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