The mass of Calcium carbonate needed : 246 g
<h3>Further explanation</h3>
Reaction
CaCO₃(s)→CaO(s)+CO₂(g)
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
Then for 55 L of CO₂, mol :
From the equation, mol ratio for mol CaCO₃ : mol CO₂ = 1 : 1, so :
mol CaCO₃ = mol CO₂ = 2.46
mass CaCO₃(MW=100g/mol) :
<u>Given: </u>
m(g) of Sulfur = 16g
Molar mass of sulfur: 32 g/mol ( from periodic table - atomic mass; mass number or 'A' - the greater number)
Molar Mass of Oxygen: 16 g/mol ( from periodic table from periodic table - atomic mass; mass number or 'A' - the greater number)
<u>Formula used: </u>
n(mol)= m (g) / M (g/mol)
Step One: <u>Write the equation </u>
S + O2 --> SO2
Step Two: <u>Balance the equation ( this one doesn't need balancing) </u>
S + O2 --> SO2
Step Three: <u>Write the molar ratios ( coefficients) </u>
S + O2 --> SO2
1 1 1 <---------molar ratio
Step Four: <u>Find the number of moles of Sulfur (mol) using the formula: </u>
n(mol)= m(g) / M (g/mol)
Substitute 16g in the mass(m) & 32 g/mol in the Molar Mass( g/mol)
n(mol)= 16 (g) / 32 (g/mol)
n(mol) = 0.5 mol of Sulfur
Step Five: <u>Using the molar ratios and the number of moles of Sulfur obtained, cross multiply to find the number of moles of Sulfur dioxide.
</u>( for future reference we don't use O2 because it is in excess, anything in excess we don't use)
S + O2 --> SO2
1 1 1 <---------molar ratio
0.5 x <---------number of moles
1 / 0.5 = 1/x
n ( Sulfur) = n ( sulfur dioxide) since the molar ratio is one to one
n( sulfur dioxide) = 0.5 moles
<span>
</span>Step Six: With<u> the given 0.5 moles for Sulfur dioxide calculated, you can find the mass of sulfur dioxide (SO2). You just have to calculate the Molar Mass of Sulfur and Oxygen by using your periodic table. Formula used:
</u>
n(mol) = m(g) / M(g/mol)
<u>Molar Mass Calculations </u>
M(O) = 16 g/mol
M(S) = 32 g/mol
M(SO2)= 32 + 16(2) = 32 + 32 = 64 g/mol.
<u>Number of moles of Sulfur dioxide calculated: </u>0.5 mol
<u>Plug in the values in their corresponding locations:
</u>
n(mol) = m(g) / M(g/mol)
0.5(mol) = m(g) / 64 ( g/mol)
m(g) = 0.5 x 64
m(g) = 32 g.
<span>FINAL ANSWER: MASS OF SULFUR DIOXIDE = 32 g.
</span>
i hope this was of help:) good luck!
Elimanate B then C and then it should be A or D just sayin i could be wrong about this i hope im right
Answer: 1.0 x 10^-3M
Explanation:
The solution with pH 3 is said to be acidic because pH values less than 7 are regarded as acidic, and will produce hydrogen ions.
Mathematically, pH is expressed as
pH = -log(H+)
where H+ is the concentration of hydrogen ion
So, pH calculations are as follows
3 = -log(H+)
(H+) = Antilog (-3)
(H+) = 0.001M
Place (H+) in standard form
(H+) = 1.0 x 10^-3M
Thus, the value of hydrogen ion (H+) in the solution with pH 3 is 1.0 x 10^-3M
N(Na)=0.255 mol
M(Na)=22.990 g/mol
m(Na)=n(Na)M(Na)
m(Na)=0.255*22.990=5.862 g