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algol13
3 years ago
14

Which statement explains why the bonds between non metals tend to be covalent?

Chemistry
2 answers:
Ostrovityanka [42]3 years ago
8 0

Answer:

C.) They have small differences in electronegativity

djverab [1.8K]3 years ago
7 0

They have small differences in electronegativity

i think thats right

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Tides are caused by the pull of gravity by the _____ and the _____.<br> (fill in the blanks)
Iteru [2.4K]

tides are caused by the gravitational force of the sun and the moon

4 0
3 years ago
Substance B was heated at first gently and then more strongly in a bunsen flame. Two gases were given off, one of them brown. A
Illusion [34]

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8 0
3 years ago
A 60.0 mL solution of 0.112 M sulfurous acid (H2SO3) is titrated with 0.112 M NaOH. The pKa values of sulfurous acid are 1.857 (
djverab [1.8K]

Answer:

a)4.51

b) 9.96

Explanation:

Given:

NaOH = 0.112M

H2S03 = 0.112 M

V = 60 ml

H2S03 pKa1= 1.857

pKa2 = 7.172

a) to calculate pH at first equivalence point, we calculate the pH between pKa1 and pKa2 as it is in between.

Therefore, the half points will also be the middle point.

Solving, we have:

pH = (½)* pKa1 + pKa2

pH = (½) * (1.857 + 7.172)

= 4.51

Thus, pH at first equivalence point is 4.51

b) pH at second equivalence point:

We already know there is a presence of SO3-2, and it ionizes to form

SO3-2 + H2O <>HSO3- + OH-

Kb = \frac{[ HSO3-][0H-]}{SO3-2}

Kb = \frac{10^-^1^4}{10^-^7^.^1^7^2} = 1.49*10^-^7

[HSO3-] = x = [OH-]

mmol of SO3-2 = MV

= 0.112 * 60 = 6.72

We need to find the V of NaOh,

V of NaOh = (2 * mmol)/M

= (2 * 6.72)/0.122

= 120ml

For total V in equivalence point, we have:

60ml + 120ml = 180ml

[S03-2] = 6.72/120

= 0.056 M

Substituting for values gotten in the equation Kb=\frac{[HSO3-][OH-]}{[SO3-2]}

We noe have:

1.485*10^-^7=\frac{x*x}{(0.056-x)}

x = [OH-] = 9.11*10^-^5

pOH = -log(OH) = -log(9.11*10^-^5)

=4.04

pH = 14- pOH

= 14 - 4.04

= 9.96

The pH at second equivalence point is 9.96

4 0
3 years ago
Seawater has a ph of 8.1. what is the concentration of oh–?
lara31 [8.8K]
PH scale is used to determine how acidic or basic a solution is.
pH can be calculated as follows;
by knowing the ph we can calculate pOH
pH + pOH = 14
pOH = 14 - 8.1 
pOH = 5.9 
pOH is used to calculate the hydroxide ion concentration 
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 1.26 x 10⁻⁶ M
therefore hydroxide ion concentration is 1.26 x 10⁻⁶ M
4 0
3 years ago
PLEASE ANSWER...........WILL MARK BRAINLIEST!!!!!!!
fomenos

Explanation:

Alkali metal cations reacts vigorously with halogens to form ionic/electrovalent compounds.

  • The alkali metals are about the most reactive metals and they belong to group I .
  • In their outermost shell, they have one valence shell electron.
  • Alkali metals are largely electropositive willing to release their valence electron to attain stability.
  • The halogens have seven electrons in their outermost shell. To complete their configuration, they need just one electron.
  • All the halogens are strongly electronegative and they are readily reactive.
  • In the vicinity of group 1 elements, they react vigorously.
  • This is due to the electrostatic attraction between the metal and non-metal ion formed.
  • Therefore, they form strong ionic bonds between their compounds.

Learn more:

sodium alkali and halogens brainly.com/question/6324347

#learnwithBrainly

4 0
4 years ago
Read 2 more answers
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