Answer:
Explanation:
10.11 g sample of 
contains 22.34% 
by mass
According to the law of constant composition the if one sample of has 22.34% of by mass then any other sample of will have the same percentage of the amount of .
For a sample of 7.09 g we have
The mass of sodium in the required sample is .
Answer:
The correct answer is KNO3
Explanation:
Pb(NO3)2 +2 KCl -> PbCl2 + KNO3
If we look at the left side of the equation we could see that there are 1 lead atom, 2 nitrate atoms ,2 potassium atoms and 2 chlorine atoms
Now when we look at the right side of the equation, we found that there are –
1 lead atom and 2 chlorine atoms (PbCl2) , thus lead and chlorine are balanced as they have the same number of atom in LHS and RHS
There is only 1 potassium and 1 nitrate atom on RHS , thus KNO3 is not balanced.
The balanced equation would be –
Pb(NO3)2 +2 KCl -> PbCl2 +2 KNO3
How will what move? What, exactly, are you asking?
Two 1+ ions are needed in order to balance one 2- ion.
Answer:
The temperature would be 304, 87 K
Explanation:
We use the formula PV= nRT:
T= PV/nR = 1,00 atm x 100L /4,00 mol x 0,082 l atm/K mol=<em>304, 87 K</em>
