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3 years ago

Which of the five most abundant elements are metals?

Chemistry

1 answer:

Gala2k [10]3 years ago

6 0

Answer:

Oxygen

Silicon

Aluminium

Iron

Calcium

Explanation:

Oxygen=47 percent

Silicon=28 percent

Aluminium=8 percent

Iron=5 percent

Calcium=3.5 percent

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The volume of carbon gas at 5.0 ATM was measured to be 363 ml. What will the pressure be if the volume is change to .00020 ml?

aleksley [76]

Answer:

The answer to your question is P2 = 9075000 atm

Explanation:

Data

Pressure 1 = P1 = 5 atm

Volume 1 = V1 = 363 ml

Pressure 2 = P2 = ?

Volume 2 = 0.0002 ml

Process

To solve this problem use Boyle's law

P1V1 = P2V2

-Solve for P2

P2 = P1V1/V2

-Substitution

P2 = (5 x 363) / 0.0002

-Simplification

P2 = 1815 / 0.0002

-Result

P2 = 9075000 atm

5 0

4 years ago

Which of the following would naturally form a cation? Ne Li O I

Lina20 [59]

Metals naturally form cations.

4 0

3 years ago

PLEASE HELP! DUE IN 5 MINUTES! ( 10 points )

max2010maxim [7]

Answer:

Explanation:

3 0

4 years ago

Read 2 more answers

Two solids, A and B, are located in the same family on the periodic table. A sample of each is placed in a beaker of HCL. Substa

Vlad [161]

What do the bubbles indicate? chemical reaction with HCl, release of H2(g)

Where the substances are located in relation to one another on the periodic table and the activity series? A is above B on the periodic table but B is above A in the activity series.

The name of the family the substances could be in ? alkaline earth, alkali metals. Either group 1 or group 2.

What substance will have a larger atomic radius? B
What substance will have a larger ionization energy? A

4 0

3 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

3 years ago