There will be a vertical asymptote when the denominator approaches zero. So the vertical asymptote is about the line x=2.
There will be a horizontal asymptote as x approaches ±oo where the y value will approach 4. So the horizontal asymptote is about the line y=4
Assuming you mean
(x-2)²=49
sqare root both sides and take positive and negative roots
x-2=+/-7
add 2 to both sides
x=2+/-7
x=2+7 and 2-7
x=9 and -5
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Answer:
(x+4)( 8x^{2}+1)
Step-by-step explanation:
:)
