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Oksanka [162]
3 years ago
12

-jk + 6m - 7jk + 4m What’s the answer please

Mathematics
2 answers:
MatroZZZ [7]3 years ago
6 0

Answer:

Step-by-step explanation:

-jk + 6m - 7jk + 4m

Combine like terms.

-8jk+10m

HTH :)

Dima020 [189]3 years ago
5 0
Combine like terms to simplify.

-jk-7jk= -8jk
6m+4m=10m
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Answer:

p= 9/4 - 3r/4

Step-by-step explanation:

Move 3r to the right and when you divide 4 from both sides and each variable, you are left with p= 9/4 - 3r/4 since you cannot simplify it more.

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Whats 2x 5=19 answer?
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According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

8 0
3 years ago
The band is raising money for their spring trip. they need to raise at
Andrews [41]

The inequality that can be used  to determine the number of boxes of donuts, d, they must sell in order to meet their goal is $1500 ≥ $575 + $5d.

<h3>What is the inequality?</h3>

Here are inequality signs and what they denote:

  • > means greater than
  • < means less than
  • ≥ means greater than or equal to
  • ≤ less than or equal to

Total amount that needs to be raised ≥ amount made at the fruit sale + (profit per box x number of boxes)

$1500 ≥ $575 + $5d

To learn more about inequality, please check: brainly.com/question/5031619

#SPJ1

8 0
2 years ago
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