Answer:
Don't post any question if isn't related to the topic or to your homework or assignment.
Explanation:
Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
Answer:
Explanation:
Types of Attractive Intermolecular Forces. Dipole-dipole forces: electrostatic interactions of permanent dipoles in molecules; includes hydrogen bonding.
This is all I can think of, I hope this has helped you.
-QueenBeauty666-
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