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Anettt [7]
3 years ago
12

Find the measure of angle 1hurry

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
8 0

Answer:

112 degrees

Step-by-step explanation:

This is a quadrilateral, meaning 4 sides. The sum of the angles of a quadrilateral is 360 degrees. You are given the right angle, or 90 degrees, and the 46 degree angle at the bottom. Since the two lines on either side of the 46 degree angle represent parallelism, angles 1 and 2 are the same.

360 - (90+46) = 224.

224 / 2 = 112.

pishuonlain [190]3 years ago
8 0

Answer:

m∠1 = 112

Step-by-step explanation:

m∠1 = m∠2

m∠1 + m∠2 + 90 + 46 = 360

m∠1 +m ∠2 + 136 = 360

m∠1 + m∠2 = 360 - 136

m∠1 + m∠2 = 224

m∠1 =  \frac{224}{2}

m∠1 = 112

m∠2 =  \frac{224}{2}

m∠2 =112

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Step-by-step explanation:

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aniked [119]
If the volume is 108, and the height is 3 meters, you would divide 108 by 3 , which is 36.
8 0
3 years ago
The function g(t)=−16t2+vt+h represents the height of an object, g, in feet, above the ground in relation to the time, t, in sec
kow [346]

Answer:

A) g(t) = - 16*t² + 80*t

B) domain is  ( 0 ≤ t ≤ 5 )

Step-by-step explanation:

A) for the model rocket

h = 0    and  v = 80 feet/sec

Then the equation     g(t)  = -16*t² + v*t + h

became

g(t) = - 16*t² + 80*t + 0         g(t) = - 16*t² + 80*t

B) The equation  g(t) = - 16*t² + 80*t  is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t)  then the biggest value for t = 5 from

-16*t²  +  80*t  ≥ 0

-16*t  ≥ -80       16*t ≤ 80

t ≤ 5

And the domain is  ( 0 ≤ t ≤ 5 )

8 0
3 years ago
If measure of the angle fhg is 61 degrees, what is measure of angle fpg (on a circle)
enyata [817]
It looks like angle FPG = twice angle FHG  - which makes sense looking at it now, but I came up with the answer another way - see attached
Download pdf
6 0
3 years ago
Need help, due ASAP. Please help.
omeli [17]

Answer:

a = 36.37 cm

c = 18.19 cm

Step-by-step explanation:

to find a, use tan

⇒ tan = \frac{opposite}{adjacent}

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tan of 60 is 1.732

⇒ 1.732 = \frac{21}{a}

multiply 21 on both sides

⇒ 1.732 x 21 = \frac{21}{a}x 21

⇒ 36.37 = a

to find c, use sine

⇒ sine = \frac{oppsosite}{hypotenuse}

⇒ sine 60 = \frac{21}{c}

sine of 60 is 0.866

⇒ 0.866 = \frac{21}{c}

muliply 21 on both sides

⇒ 0.866 x 21 = \frac{21}{c} x 21

⇒ 18.19 = c

4 0
3 years ago
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