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3 years ago

Fully explain, why each characteristic would or would not favor the formation of an amorphous solid

Chemistry

1 answer:

WARRIOR [948]3 years ago

5 0

Answer:

Crystalline solids have regular ordered arrays of components held together by uniform intermolecular forces, whereas the components of amorphous solids are not arranged in regular arrays. The learning objective of this module is to know the characteristic properties of crystalline and amorphous solids. When cleaved or broken, they produce fragments with irregular, often curved surfaces; and they have poorly defined patterns when exposed to x-rays because their components are not arranged in a regular array. An amorphous, translucent solid is called a glass.

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What is the molecular formula of a compound with the empirical formula NO¿ and a molar mass of 138.02 grams per mole?

GuDViN [60]

Molar mass of N = 14 g/mol
Molar mass of O2 = 32 g/mol
Adding both masses = 46 g/mol
Actual molar mass/ Empirical molar mass = 138.02 / 46 = 3
Now multiplying this co effecient with empirical fomula NO2 = 3(NO2)
= N3O6
So according to above explanation,
<span>D) N3O6, is the correct answer.</span>

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4 years ago

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4. Why does liquid water take on the shape of a cup it is poured into, but solid ice cubes do

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Answer:

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3 years ago

It is difficult to break the ionic bonds in a compound because of the...

mestny [16]

The answer to the first one is C. Strong attraction between ions

The answer to the second one is A. High melting points

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4 years ago

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If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH

KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

$M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)$

$M_{KOH}=0.113 M\\V_{KOH}=79.06 mL$

$V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????$

$M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}$

$M_{CH3COOH} = \frac{0.113*79.06}{95.27}$

$M_{CH3COOH} = 0.094 M$

Moles of $CH_3COOH$ = $95.27* 10^{-3}* 0.094$

=0.0090 moles

Moles of $KOH = 79.06*10^{-3}*0.113$

= 0.0090 moles

The equation for the reaction can be expressed as :

$CH_3COOH$ $+$ $KOH$ -----> $CH_3COO^{-}K^+$ $+$ $H_2O$

Concentration of $CH_3COO^{-$ ion = $\frac{0.0090}{Total volume (L)}$

= $\frac{0.0090}{(95.27+79.06)} *1000$

= 0.052 M

Hydrolysis of $CH_3COO^{-$ ion:

$CH_3COO^{-$ $+$ $H_2O$ -----> $CH_3COOH$ $+$ $OH^-$

$K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}$

⇒ $\frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}$

= $0.5494*10^{-9}= \frac{x*x}{0.052-x}$

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

$0.5494*10^{-9}= \frac{x^2}{0.052}$

$x^2 = 0.5494*10^{-9}*0.052$

$x^2 = 0.286*10^{-10$

$x = \sqrt{0.286*10^{-10$

$x =0.535*10^{-5}M$

$[OH] = x =0.535*10^{-5}$

$pOH = -log[OH^-]$

$pOH = -log[0.535*10^{-5}]$

$pOH = 5.27$

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0

3 years ago

Which memrane lines the abdomino pelvic cavity

Scilla [17]

Answer:

The peritoneum

Explanation:

The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.

hope it helps, and pls answer this brainly.com/question/22410918

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3 years ago

Fully explain, why each characteristic would or would not favor the formation of an amorphous solid​

Fully explain, why each characteristic would or would not favor the formation of an amorphous solid