I believe the answer is 50.5 molecules
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of
are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity = 
1.500 M = 
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of
to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
Answer:
2.13g
Explanation:
Atomic mass of CO2 = 12 + 32 = 44g/Mol
Atomic mass of C3H8 = 36 + 8 = 44g/Mol
Reaction
C3H8 + 5O2 --> 3CO2 + 4H2O
3CO2 = 6.39g
Required C3H8 = (6.39/(44 x 3)) x 44 = 2.13g
Answer: 
Explanation:
Firstly, we have to find the Molecular mass of potassium oxide (
):
atomic mass: 39 u
atomic mass: 16 u
molecular mass: 
This means that in 1 mole of
there are
and we need to find how many moles there are in
:
1 mole of
-----
of 
-----
of 

This is the quantity of moles in 73.9 g of potassium oxide
Now we can calculate the number of atoms in 73.9 g of potassium oxide by the following relation:

Where:
is the number of atoms in 73.9g of potassium oxide
is the Avogadro's number, which is determined by the number of particles (or atoms) in a mole.
Then:

This is the quantity of atoms in 73.9g of potassium oxide