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liraira [26]
3 years ago
11

What is the formula mass of the fictitious compound: AB2?

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0
For a molecule AB2, 3.5g of A represents one molar fraction, and 8.00g B represents 2 molar fractions (or 4.0+4.0). Therefore, a direct ratio can be given as 3.5:4.0, or 1:1.14. This means a molecule AnBm will give a mass ratio for A:B of n:1.14xm

For a molecule AB, for every 1g of A, you will have 1.14g of B.

For a molecule AB2, for every 1g of A, you will have 2.28g of B.

For a molecule A2B3, for every 1g of A, you will have (1.14x3/2) 1.71g of B.
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Answer:

12.5 g of Li are needed in order toproduce 0.60 moles of Li₃N

Explanation:

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6Li(s) + N₂(g) → 2Li₃N(s)

If nitrogen is in excess, the lithium is the limiting reactant.

Ratio is 2:6

2 moles of nitride were produced by 6 moles of Li

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Let's convert the moles to mass → 1.8 mol . 6.94 g/ 1mol = 12.5 g of Li

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3 years ago
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MrMuchimi

Answer:

<u><em>The correct option is C) the moon takes the same time to rotate and revolve.</em></u>

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Other options, like option D, is not correct because there will be craters on the other side of the moon too. But as we see the same side of the moon, hence we cannot see the craters present on the other side of the moon.

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