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liraira [26]
3 years ago
11

What is the formula mass of the fictitious compound: AB2?

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0
For a molecule AB2, 3.5g of A represents one molar fraction, and 8.00g B represents 2 molar fractions (or 4.0+4.0). Therefore, a direct ratio can be given as 3.5:4.0, or 1:1.14. This means a molecule AnBm will give a mass ratio for A:B of n:1.14xm

For a molecule AB, for every 1g of A, you will have 1.14g of B.

For a molecule AB2, for every 1g of A, you will have 2.28g of B.

For a molecule A2B3, for every 1g of A, you will have (1.14x3/2) 1.71g of B.
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Consider the formula al2(so4)3. how many atoms of aluminum are present?
Shkiper50 [21]
2 atoms of aluminium
3 0
3 years ago
Fake answers are reported and your account will be banned
Leona [35]

Answer:

BRAINLIEST?

Explanation:

Ammonia is a typical weak base. Ammonia itself obviously doesn't contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions. My findings said that ammonia is a weak base, potassium hydroxide is a strong base, vinegar is a weak acid and ethyl alcohol is a weak acid.

Vinegar and ethyl alcohol are eliminated as they are acids. The question is on bases.... Potassium hydroxide is a strong base. So we are left with ammonia, being a weak base.

A is your answer

8 0
3 years ago
Read 2 more answers
If 60 grams of a liquid takes up 120ml how dense is the liquid
Black_prince [1.1K]

Answer:

<h2>Density = 0.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question

mass = 60 g

volume = 120 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{60}{120}  \\  =  \frac{1}{2}</h3>

We have the final answer as

<h3>Density = 0.5 g/mL</h3>

Hope this helps you

4 0
3 years ago
Major Battles of the
san4es73 [151]
Answer: Lexington and Concord

Explanation: The British were trying to find weapons and could not find them.
8 0
3 years ago
7. Diethyl ether burns in air according to the following equation. C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l) If 7.15 L of CO2 is
iren [92.7K]

From the stoichiometry of the combustion reaction, we can see that 7.4 L of oxygen is consumed.

<h3>What is combustion?</h3>

Combustion is a reaction in which a substance is burnt in oxygen. The equation of the reaction is; C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l)

We can obtain the number of moles of CO2 from;

PV = nRT

n = 1.02 atm * 7.15 L/0.082 atm LK-1mol-1 * (125 + 273) K

n = 7.29 /32.6

n = 0.22 moles

If 6 moles of oxygen produces 4 moles of CO2

x moles of oxygen produces 0.22 moles of CO2

x = 0.33  moles

1 mole of oxygen occupies 22.4 L

0.33 moles of oxygen occupies 0.33 moles *  22.4 L/ 1 mole

= 7.4 L of oxygen

Learn more about stoichiometry: brainly.com/question/13110055

#SPJ1

6 0
2 years ago
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