The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.
Evidently, the shell with energy level one has no p orbital.
- Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.
- However, we must know that the p-orbital comprises of 3 sub-orbitals namely;
p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.
- Therefore, the total number of electrons in the p orbital is 6 electrons.
In essence, the element in question should have electron configuration;
- 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
The electron configuration above contains 54 electrons and has atomic number, 54.
In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.
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Answer:
The mass number
Explanation:
neutrons + protons = mass number
Answer: Option (A) is the correct answer.
Explanation:
Chemical equation for the given reaction is as follows.
And, the expression to calculate pH of this reaction is as follows.
pH = ![pk_{a} + log \frac{[HCOO^{-}]}{[HCOOH]}](https://tex.z-dn.net/?f=pk_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BHCOO%5E%7B-%7D%5D%7D%7B%5BHCOOH%5D%7D)
As the concentration of 
is directly proportional to pH. Hence, when there occurs a decrease in the pH of the solution the ![[HCOO^{-}]](https://tex.z-dn.net/?f=%5BHCOO%5E%7B-%7D%5D)
will also decrease.
Thus, we can conclude that the statement, HCOO will accept a proton from HCl to produce more HCOOH and 
, best supports the student's claim.
Sublimation takes place when an element or compound changes directly from a solid into a gas without passing through the liquid state....
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