If we randomly pick two persons from the population, each one will have a probability of 1-1/28=27/28 of being a non-carrier.
Thus for neither to be non-carrier, the probability is the product of the individual probabilities since the picks are assumed independent (with a large enough population).
Probability = (27/28)*(27/28) = 729/784
or approximately 0.930
It would be...C?? I'm not sure but I think it's right. Brainliest?
Usually if it's an basic good, or very important one.
because the price fluctuations do not affect the quantity sold.
a good example of that would be milk, if the milk gallon is say $8, and a family needs 1 gallon daily, they buy it for $8.
if the price drops to $7, they might buy 2, but they only need 1 everyday, just in case they may get another.
if the price drops to $4 or even $3, they're not going to get 10 gallons, there's no need for it on an everyday basis, besides is a perishable.
now if the price goes up to $12, they still need it, and will buy it for $12.
Answer:
90% confidence interval -> {0.4529, 0.5871}
Step-by-step explanation:
<u>Check conditions for a 1-proportion z-interval:</u>
np>10 -> 150(0.52)>10 -> 78>10 √
n(1-p)>10 -> 150(1-0.52)>10 -> 72>10 √
Random sample √
n>30 √
For a 90% confidence interval, the critical value is z=1.645
The formula for a confidence interval is:
CI = p ± z√[p(1-p)/n]
<u>Given:</u>
p = 78/150 = 0.52
n = 150
z = 1.645
Therefore, the 90% confidence interval is:
CI = 0.52 ± 1.645√[0.52(1-0.52)/150] = {0.4529, 0.5871}
Context: We are 90% confident that the true proportion of all voters who
plan to vote for the incumbent candidate is contained within the interval
