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Murljashka [212]
2 years ago
5

You receive results from the team engagement survey. According to the survey, your team members feel that the feedback they prov

ide to management is not being taken into consideration quickly enough. Assuming all options are possible, what would you be most and least likely to do?
Business
1 answer:
andrew-mc [135]2 years ago
7 0

Answer: Most: Discuss the issue with your team. Ask team members for suggestions on how to better incorporate their

Least: Talk to your peers who received similar feedback and brainstorm together on how to better engage the team.

Explanation:

You probably wish you could get more input from your employees if you're like most managers. Quality feedback will help all of you work together, improve your style of leadership, and make sure you catch problems before they become big issues.

While the members of your team must be the ones to come up with the ideas, there are many things you can do to make it better and more productive to produce them.

Your methodology offers an example.

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Which of the following statements is CORRECT? a. The present value of a 3-year, $150 annuity due will exceed the present value o
lorasvet [3.4K]

Answer:

Statement a. is correct.

Explanation:

The effective annual rate is always higher than the nominal interest rate, as the formula is clear for any number of periods, for any interest rate:

Effective Annual Rate of return = (1 + \frac{i}{n})^n - 1

Further if we calculate the present value of annuity due and ordinary annuity assuming 6 % interest rate, then:

Present value of annuity due =

(1 + 0.06) \times 150 \times (\frac{1 - \frac{1}{(1 + 0.06)^3} }{0.06} )

= 1.06 \times $400.95

= $425.0089

Present value of ordinary annuity = 150 \times (\frac{1 - \frac{1}{(1 + 0.06)^3} }{0.06} )

= $150 \times 2.6730

= $400.95

Therefore, value of annuity due is more than value of ordinary annuity.

Statement a. is correct.

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3 years ago
The increasing participation of women in the labor force has been termed the:
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<span>Women participating in the labor force is known as shattering the glass ceiling. The term originated in the 1980s and refers to woman who are moving up in the business world.</span>
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3 years ago
Three weeks after Abed died, his brother Tony properly received Abed’s last paycheck from his employer. The gross amount of the
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Answer:

The best answer is "A"

It is deductible both on Tony's income tax return and on Abe's estate tax return

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Identify four (4) different types of credit (purposes)
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The College Board reported the following mean scores for the three parts of the Scholastic Aptitude Test (SAT) (The World Almana
storchak [24]

Answer:

a) P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

b) P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

c) P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores for critical reading of a population, and for this case we know the distribution for X is given by:

X \sim N(502,100)  

Where \mu=502 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(502-10 < \bar X < 502+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(492

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 0.949)= P(Z

Part b

Let X the random variable that represent the scores for Math of a population, and for this case we know the distribution for X is given by:

X \sim N(515,100)  

Where \mu=515 and \sigma=100

We select a sample of size n=90, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{90}}=10.54)

And for this case we want this probability:

P(515-10 < \bar X < 515+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(505

And we can use excel or the normal standard table to find this probability:

P(-0.949 < Z< 1.898)= P(Z

Part c

Let X the random variable that represent the scores for Writing of a population, and for this case we know the distribution for X is given by:

X \sim N(494,100)  

Where \mu=494 and \sigma=100

We select a sample of size n=100, since the distribution for X is normal then the distribution for the sample size is also normal

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}=\frac{100}{\sqrt{100}}=10)

And for this case we want this probability:

P(494-10 < \bar X < 494+10)

And for this case we can use the z score given by:

z= \frac{\bar X -\mu}{\sigma_{\bar x}}

And if we use this formula we got:

P(484

And we can use excel or the normal standard table to find this probability:

P(-1 < Z< 1)= P(Z

3 0
3 years ago
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