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Tcecarenko [31]
3 years ago
6

I need to know the surface area of this prism please help !!!! I will give brainlist !

Mathematics
2 answers:
aivan3 [116]3 years ago
4 0

Answer:

614

Step-by-step explanation:

15 x 13 = 195    two times   195 x 2 = 390

4 x 15 = 60    two times   60 x 2 = 120

4 x 13 = 52      two times   52 x 2 = 104

104 + 120 + 390 = 614

nevsk [136]3 years ago
4 0

Answer:

SA = 2(l·w)+2(w·h)+2(l·h)

SA = 614 sq in

Step-by-step explanation:

SA = 2(4x13)+2(13x15)+2(4x15)

= 2(52)+2(195)+2(60)

= 104 + 390 + 120

= 614

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Help pleaseeeeeeeeeeeeee!!!!!!!!!!!!!!!! T^T
artcher [175]
1 + (-5/8) = 3/8

Explanation: If the coffee wasn’t drank it would’ve been at fraction 1 (or 100%)

Since he drank 5/8 of it. The coffee left is now 1-(5/8)

But since the question has asked to give the equation in addition format. Put a plus sign in between the two.

Therefore,
1 + (-5/8)

Solve it,
= 1-(5/8)
= (8-5)/8
= 3/8

Hence the equation is:

1 + (-5/8) = 3/8.
8 0
3 years ago
Read 2 more answers
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
Using the substitution method, answer the question.<br><br> y=4x-3<br> y=-x+7
Nutka1998 [239]
Basically they're both equal
4x-3=x+7
-x. -x
3x-3=7
+3 +3
3x=10

X=10/3
7 0
3 years ago
anyone know the answer i worked it out but didn't know where i messed up so i am just gonna ask for someone to help me with it.
hram777 [196]
I also worked it out but I got -5/3

2(6p-5) ≥ 3(p-8) -1

12p-10 ≥ 3p-24-1

12p-10 ≥ 3p-25

12p-3p ≥ -25+10

9p ≥ -15

-15/9

P ≥ -5/3
5 0
3 years ago
You need to find the width of the stream. You cannot measure the width directly, so you draw a diagram showing lengths that you
MAXImum [283]
There is no diagram, therefore we can't answer the question.
4 0
3 years ago
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