All categories

3 years ago

The distance between particles______when the temperature increases and

Chemistry

1 answer:

LekaFEV [45]3 years ago

5 0

Answer:

increases

decreases

Explanation:

The distance between particles increases when the temperature increases and decreases when temperature decreases.

Temperature changes in a system causes the particle of such system to behave in different ways.
When particles gain heat energy as their temperature increases, they begin to move further apart.
As their temperature reduces they tend to coalesce.

You might be interested in

What is metallic character

Natalka [10]

Answer:

<h3>METALLIC CHARACTER </h3>

<h3>DEFINITION </h3>

The metallic character is a property that is unique to metals. It indicates the reactivity of a metal atom

Explanation:

HOPE IT'S HELPFUL THANKS

4 0

2 years ago

HCOOH is: formaldehyde formic acid acetone carbon hydroxide

Afina-wow [57]

HCOOH is formic acid

3 0

3 years ago

Read 2 more answers

A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55

Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

<u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol$

<u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

$0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol$

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

$0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL$

Hence, the volume of NaOH required is 402.9 mL

6 0

3 years ago

Two members of the Boron family owe their names to bright lines in their emission spectra. Indium has a bright indigo blue line

uranmaximum [27]

Answer:

E Indium = 4.407 x 10⁻¹⁹ J

E Thallium = 3.716 x 10⁻¹⁹ J

Explanation:

From Planck´s equation for a given wavelength, the energy is given by.

E = h ( c/ λ )

h: Planck´s constant, 6.626 x 10⁻³⁴ J·s

c: light speed, 3 x 10⁸ m/s

λ: wavelength in m

We will need first to convert the given wavelengths to m:

451.1 nm x ( 1 m/10⁹ nm ) = 4.511 x 10⁻⁷ m

535.0 nm x ( 1 m/10⁹ nm ) = 5.350 x 10⁻⁷ m

E Indium = 6.626 x 10⁻³⁴ J·s x 3x 10 ⁸ m/s/ 4.511 x 10⁻⁷ m = 4.407 x 10⁻¹⁹ J

E Thallium = 6.626 x 10⁻³⁴ J·s x 3x 10 ⁸ m/s/ 5.350 x 10⁻⁷ m = 3.716 x 10⁻¹⁹ J

4 0

4 years ago

What is the molarity of ZnCl2 that forms when 25.0 g of zinc completely reacts with CuCl2 according to the following reaction? A

zalisa [80]

Molarity of $\mathrm{ZnCl}_{2}$ is <u>1.364 M</u>

<u>Explanation</u>:

Molarity of product Zinc Chloride which is formed when 25.0 g of Zinc completely reacts with copper(II) chloride: $\mathbf{Z n}(\mathbf{s})+\mathbf{C u C l}_{2}(\mathbf{a q}) \rightarrow \mathbf{Z n C l}_{2}(\mathbf{a q})+\mathbf{C u}(\mathbf{s})$