Answer:
Explanation:
a. CuO+ 2HCl⇒CuCl2+ H2O
b.
=
= 0,05 (mol)
⇒
=
=0,05 mol
⇒
= 0,05×135=6,75 (g)
c.
=2×
=0,1 (mol)
⇒
= 0,1×36,5= 3,65 (g)
⇒
=
×100=36,5 (g)
⇒ Nồng độ phần trăm dd sau phản ứng= Nồng độ % dd CuCl2=
×100=
×100≈ 16,67%
Answer: 0.00867 moldm-3
Explanation:
Since the reaction is 1st order,
Rate of reaction=∆[A]÷t
0.646-0.0146/72.8= 0.00867
Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.
M=D*V,
V=m/D
m=15 g
D=3 g/ml
V=15 g/3 g/ml=5 ml
If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component =

number of moles of ethanol - 3.00 mol
total number of moles in mixture - 3.00 + 5.00 = 8.00 mol
mole fraction of ethanol =

mole fraction of ethanol is 0.375