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LenaWriter [7]
3 years ago
6

Does temperature change during a chemical reaction?​

Chemistry
2 answers:
Serga [27]3 years ago
7 0

Answer: Yes

Explanation: Temperature change is a type of chemical reaction, caused by the effect the two reactants have on each other when mixed.

Anarel [89]3 years ago
4 0

Answer: yes

Explanation:

Not all the time, but temperature change can happen during a chemical reaction.

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Is the following equation balanced? Why or why not?<br> N, + 6H2 → 2NHO
Fiesta28 [93]

Answer:

No

Explanation:

There is only one Nitrogen on the left side while there are 2 on the right. Also there is zero oxygen on the left side and two on the right. The amounts of hydrgen arent equal to each side either.

6 0
4 years ago
Are these gases lighter than or denser than air? How can you tell?
kotegsom [21]
Some Gases are lighter than air
Remember,Air is a mixture of gases
So you cant tell!
It depends on the gas
Hope i helped
3 0
3 years ago
3) What are the three types of sedimentary rocks?
astraxan [27]

Answer:

clastic, organic, and chemical

8 0
3 years ago
Potassium-40 is a radioactive isotope that decays into a single argon-40 atom and other particles with a half-life of 1:25 billi
stiks02 [169]

Answer:

0.147 billion years = 147.35 million years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of Potassium-40 is 1.25 billion years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.25 billion years) = 0.8 billion year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

<em></em>

where, k is the rate constant of the reaction (k = 0.8 billion year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (Potassium-40) ([A₀] = 100%).

[A] is the remaining concentration of (Potassium-40) ([A] = 88.88%).

  • At the time needed to be determined:

<em>8 times as many potassium-40 atoms as argon-40 atoms. Assume the argon-40 only comes from radioactive decay.</em>

  • If we start with 100% Potassium-40:

∴ The remaining concentration of Potassium-40 ([A] = 88.88%).

and that of argon-40 produced from potassium-40 decayed = 11.11%.

  • That the ratio of (remaining Potassium-40) to (argon-40 produced from potassium-40 decayed) is (8: 1).

∴ t = (1/k) ln([A₀]/[A]) = (1/0.8 billion year⁻¹) ln(100%/88.88%) = 0.147 billion years = 147.35 million years.

8 0
3 years ago
The burning of fossil fuels results in which type of chemical reaction
Alika [10]
It results in a combustion reaction
5 0
4 years ago
Read 2 more answers
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