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3 years ago

The average atomic mass for any element will be closest to the average atomic mass of the ________ isotope.

Chemistry

1 answer:

dezoksy [38]3 years ago

5 0

Answer:

Explanation:

The average atomic mass for any element will be closest to the average atomic mass of the __different______ isotopes.

To calculate the average atomic mass of any element, the mass spectrometry method helps to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called the geonormal abundance or abundance. From this, the average atomic mass of an element from different isotopes can be calculated.

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Potassium bromide conducts electricity when ______

amm1812

Answer:

When melted or dissolved in water.

Explanation:

Potassium bromide in its solid form contains ions, which are charged atoms. Through the heating process, the melted potassium bromide becomes an ionic liquid. If solid potassium bromide is dissolved, for example in water, the resulting release of ions allows it to conduct electricity.

3 0

2 years ago

Explain why beryllium is produced when potassium is heated with beryllium

Vladimir [108]

Explanation:

The more reactive element replaces less reactive element during chemical reaction.

Since, potassium is more reactive than beryllium. When potassium reacts with beryllium choride, it replaces beryllium and forms potassium chloride and produces beryllium.

3 0

2 years ago

4.1 moles of sodium carbonate to molecules of sodium carbonate.

docker41 [41]

<h3>Answer:</h3>

2.47 × 10^24 molecules

<h3>Explanation:</h3>

One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.

That is, 1 mole of a compound = 6.022 × 10^23 molecules

Therefore,

1 mole of Na₂CO₃ = 6.022 × 10^23 molecules

Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃

we get,

= 4.1 moles × 6.022 × 10^23 molecules

= 2.47 × 10^24 molecules

Hence, 4.1 moles of Na₂CO₃ contains 2.47 × 10^24 molecules

3 0

3 years ago

Give the hybridization for the c in hcch. group of answer choices

Tamiku [17]

The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.

Discussion:

There are three different forms of hybridization -

sp- The first occurs when two carbon atoms are triple linked.
sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
sp₃- When a single bond joins two carbon atoms, this is known as sp₃.

In the case of acetylene(HCCH or C₂H₂):

The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.

H-C≡C-H

Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.

Learn more about hybridization here:

brainly.com/question/14140731

#SPJ4

5 0

1 year ago

A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p

Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL$

Putting values in above equation, we get:

$3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M$

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0

3 years ago