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3 years ago

The average atomic mass for any element will be closest to the average atomic mass of the ________ isotope.

Chemistry

1 answer:

dezoksy [38]3 years ago

5 0

Answer:

Explanation:

The average atomic mass for any element will be closest to the average atomic mass of the __different______ isotopes.

To calculate the average atomic mass of any element, the mass spectrometry method helps to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called the geonormal abundance or abundance. From this, the average atomic mass of an element from different isotopes can be calculated.

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What is the bond order for a single covalent bond?

hram777 [196]

Answer:

We typically represent covalent bonds with a dash ( - ) between the atoms. This indicates a single bond. Ex: Cl - Cl

Single bond, double bond, triple bond.

Explanation:

We call it a single covalent bond because the atoms are sharing a single pair of electrons.

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3 years ago

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Explanation:

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2 years ago

2. Calculate the pl of the following amino acids(use their Pka values) a. Arginine b. Glutamic acid of water an c. Asparagine d.

Savatey [412]

<h2>♨ANSWER♥</h2>

pl (25*C)

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1 year ago

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight

Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒ $Mass \ of \ Butane = Density\times Volume$

On putting the estimated values, we get

⇒ $=0.579\times 7.96$

⇒ $=4.60 \ g$

6 0

3 years ago

Write a balanced half-reaction describing the reduction of aqueous vanadium(V) cations to aqueous vanadium(I) cations.

11Alexandr11 [23.1K]

Explanation:

Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.

Reduction takes place at the cathode.

In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.

The half reaction is :

$V^{5+}(aq)+4e^- \rightarrow V^{1+}(aq)$

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3 years ago

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