The distance is 97720.5 m
From the question, we have
P = 0.06 W × 2 = 0.12 W
d = ?
Sound intensity, I = P/4πd²
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
The distance is 97720.5 m
Sound intensity :
The power carried by sound waves per unit area in the direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. Sound intensity is a measure of how quickly energy moves across a given space. The unit area in the SI measurement system is 1 m2. So Watts per square meter are used to measure sound intensity. As there will be energy flow in certain directions but not in others, sound intensity also provides a measure of direction.
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Answer:
0.002833 sec
Explanation:
Speed of light in vacuum is 
Given distance = 850 km = 850×1000=850000 m
We have to calculate the time that light take to travel the distance 850 km
Time 
So the time taken by light to travel 850 km is 0.002833 sec
Answer:
Explanation:
- For diagram refer the attachment.
It is given that five cells of 2V are connected in series, so total voltage of the battery:

Three resistor of 5
, 10
, 15
are connected in Series, so the net resistance:



According to ohm's law:


On substituting resultant voltage (V) as 10 V and resultant resistant, as 30
we get:


The electric current passing through the above circuit when the key is closed will be <u>0.33 A</u>