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bonufazy [111]
3 years ago
15

I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?

Physics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

<em>B. 68.6m</em>

Explanation:

<u>Free Fall Motion </u>

When a body is left to move in the air with no friction, the motion is ruled only by the force of gravity. The vertical distance a body travels in the air after a time t is .

\displaystyle y=\frac{gt^2}{2}

We know the egg takes 3.74 seconds to reach the ground. The height it was launched from is

\displaystyle y=\frac{(9.8)(3.474)^2}{2}

\displaystyle y=68.54\ m

The closest correct option is

B. 68.6m

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A projectile is fired with an initial speed of 150 m/s and angle of elevation 60°. (Recall g ≈ 9.8 m/s2. Round your answers to t
natka813 [3]

Answer:

1988 m

Explanation:

Range of a projectile

R = U²sin2∅/g...................... Equation 1

Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.

Given: U = 150 m/s, ∅ = 60°

Constant: g = 9.8 m/s².

Substitute these values into equation 1

R = 150²(sin60°)/9.8

R = 22500(0.866)/9.8

R = 1988 m

Hence the Range of the projectile is 1988 m

4 0
3 years ago
This spectrometer reading shows some red, blue, and purple. Our atom is most likely ______________________.
Kisachek [45]
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7 0
3 years ago
A 7.45 nC charge is located 1.66 m from a 4.22 nC point charge. (a) Find the magnitude of the electrostatic force that one charg
BaLLatris [955]

Answer:

a.F=1.03\times 10^{-7}N

b.Repulsive

Explanation:

We are given that

q_1=7.45nC=7.45\times 10^{-9}C

1nC=10^{-9}C

q_2=4.22nC=4.22\times 10^{-9}C

r=1.66m

We know that

Electrostatic force =F=k\frac{q_1q_2}{r^2}

r=Distance between q_1\;and\;q_2

k=Constant=9\times 10^9Nm^2C^{-2}

Using the formula

a.The magnitude of the electrostatic force=F=\frac{9\times 10^9\times 7.45\times 10^{-9}\times 4.22\times 10^{-9}}{(1.66)^2}

The magnitude of the electrostatic force=F=1.03\times 10^{-7}N

b.Both charge are positive .We know that when like charges repel each other and unlike charges attract to each other.

Therefore, the force between given charges is repulsive.

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3 years ago
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Answer:

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Answer:

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Explanation:

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