Question

Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational potential energy does the object undergo if it is released from rest 16.0 m above the ground and ends up 1.30 m above the ground ? Change in gravitational potential energy:

Answer 1

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is $m=2250\ kg$

The initial height of dropping is $h_1=16\ m$

The final height of dropping $h_2=1.3\ m$

Gravitational potential energy is the function of height i.e.

$\Rightarrow \text{G.E.}=mgh$

Change in Gravitational Energy is

$\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ$