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jasenka [17]
2 years ago
10

Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational poten

tial energy does the object undergo if it is released from rest 16.0 m above the ground and ends up 1.30 m above the ground ? Change in gravitational potential energy:
Physics
1 answer:
den301095 [7]2 years ago
5 0

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is m=2250\ kg

The initial height of dropping is h_1=16\ m

The final height of dropping h_2=1.3\ m

Gravitational potential energy is the function of height i.e.

\Rightarrow \text{G.E.}=mgh

Change in Gravitational Energy is

\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ

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Answer:

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Explanation:

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How do human population growth trends differ between developed nations and developing nations?
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3 years ago
In a liquid with a density of 1400 kg/m3 , longitudinal waves with a frequency of 370 Hz are found to have a wavelength of 8.40
VARVARA [1.3K]

Answer:

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Explanation:

given data

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frequency = 370 Hz

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solution

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we know Bulk Modulus = v^2*\rho   ...............

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and v is =  frequency × wavelength

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3 years ago
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Answer:

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