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erastova [34]
3 years ago
6

Two cars are traveling along a straight line in the same direction, the lead car at 24.7m/s and the other car at 29.9m/s. at the

moment the cars are 38.1m apart, the lead driver applies the brakes, causing her car to have an acceleration of -1.96m/s2. how long does it take for the lead car to stop? (in s)
Physics
1 answer:
sattari [20]3 years ago
7 0

Answer: 12.6 s

We would use the equation of motion:

v-u=at

where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

It is given that the lead car has an initial velocity, u=24.7\hspace{1mm} m/s. It decelerates with a=-1.96 \hspace{1mm} m/s^{2} to stop (v=0). we need to calculate the time taken by the lead car to stop.

\Rightarrow t=\frac{v-u}{a}\\ \Rightarrow t=\frac{0-24.7}{-1.96}=12.6\hspace{1mm} s

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hodyreva [135]

Answer:

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Explanation:

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3 years ago
A boy drags a box of toys.It experiences a frictional force of 10N .calculate acceleration of the system
hodyreva [135]

Answer:

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7 0
3 years ago
What is the acceleration of an object with a constant velocity
valina [46]

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Since in your case there is no change, there is no acceleration, so it is zero:

Or in formula: <span>a=<span><span>Δv</span>t</span></span>

Where a=acceleration, <span>Δv</span>=change in velocity and t=time

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Heat is the answer but I need to use 20 characters to post :)
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soldi70 [24.7K]

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