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3 years ago

How atoms are in one mole of patassuim

Physics

1 answer:

lord [1]3 years ago

6 0

Answer:

There are 6.022 × 10²³ atoms of potassium in every mole of potassium.

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A 0.0434-m3 container is initially evacuated. Then, 4.19 g of water is placed in the container, and, after some time, all of the

adell [148]

Answer:

P =18760.5 Pa

Explanation:

Given that

Volume ,V= 0.0434 m³

Mass ,m= 4.19 g = 0.00419 kg

T= 417 K

If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation

Ideal gas equation P V = m R T

p=Pressure ,V = Volume ,m =mass

T=Temperature ,R=Universal gas constant

Now by putting the values

P V = m R T

For water R= 0.466 KJ/kgK

P x 0.0434 = 0.00419 x 0.466 x 417

P =18.7605 KPa

P =18760.5 Pa

Therefore the answer is 18760.5 Pa

6 0

3 years ago

Astronauts aboard the U.S.S. Burger decide to fire the rocket thrusters for 3.0 seconds to make a course correction. While the t

Cloud [144]

Answer:

340 m/s

Solution:

As per the question;

Time, t = 3.0 s

Total distance moved by the ship, d = 10,500 km

The increase in speed, v = 340 m/s

Now,

To calculate the U.S.S Burger's change in speed, $\Delta V$ :

The final velocity is given by:

$v_{f} = 340 + v_{i}$ (1)

where

$v_{f} = final\ velocity$

$v_{i} = initial\ velocity$

Also, the change in velocity is given by:

$\Delta v = v_{f} - v_{i}$ (2)

Now, from eqn (1) and (2):

$\Delta = 340 + v_{i} - v_{i} = 340\ m/s$

8 0

3 years ago

The driver of a car traveling at a speed of 27 m/s slams on the brakes and comes to a stop in 3 s. If we assume that the speed c

NISA [10]

Answer:

Average speed = 13.5 m/s

Explanation:

Since the car is running at a speed of 27 m/s and it stops after 3 seconds by applying the brake. Therefore, the initial speed of the 27 m/s and final speed is 0.

Use below formula to find the average speed :

Average speed = (Initial speed + final speed ) / 2

Average speed = (27 + 0 ) / 2

Average speed = 13.5 m/s

7 0

3 years ago

I shared a picture of the problem. It’s a basic Physics question and an Algebra question.

julia-pushkina [17]

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

Given the expressions;

$T_s = 2 \pi \sqrt{\frac{m}{k} } \ and \ T_s = \frac{2 \pi}{\omega}$

Equating both expressions we will have;

$2 \pi \sqrt{\frac{m}{k} } = \frac{2 \pi}{\omega}$

Divide both equations by 2π

$\frac{2 \pi\sqrt{\frac{m}{2 \pi} } }{2 \pi}=\frac{\frac{2 \pi}{\omega} }{2\pi}\\\sqrt{\frac{m}{2 \pi} } = \frac{1}{\omega}\\$

Square both sides

$(\sqrt{\frac{m}{k} } )^2 = (\frac{1}{\omega} )^2\\\frac{m}{k} = \frac{1}{\omega ^2} \\\omega ^2 = \frac{k}{m}$

Take the square root of both sides

$\sqrt{\omega ^2} =\sqrt{\frac{k}{m} } \\\omega = \sqrt{\frac{k}{m}$

Hence the expression of ω in terms of m and k is

$\omega = \sqrt{\frac{k}{m}$

3 0

3 years ago

All the organelles in a cell work together to help the cell and the whole organism function. Some diseases are caused by the fai

soldier1979 [14.2K]

The correct answer is cell membrane

5 0

3 years ago

Read 2 more answers