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3 years ago

How much electrical energy is used by a 400 W toaster that is operating for 5

Physics

1 answer:

andrew11 [14]3 years ago

8 0

Answer:

The answer is C. 120,000 J.

Explanation:

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You wish to cook some pasta and so take some water and heat it on a stove. If you use 2000 grams of water with an initial temper

Ronch [10]

Answer:

the stove energy went into heating water is 837.2 kJ.

Explanation:

given,

mass of water = 2000 grams

initial temperature = 0° C

Final temperature = 100° C

specific heat of water (c) = 4.186 joule/gram

energy = m c Δ T

= 2000 × 4.186 × (100° - 0°)

= 837200 J

= 837.2 kJ

hence, the stove energy went into heating water is 837.2 kJ.

3 0

3 years ago

Explain how energy allows a paper clip to be attracted to a magnet

ELEN [110]

I really don’t know maybe energy from the poles just attaches and the soil comes and energy lifts the matter of soil and the magnet follows and lifts and goes up to the soil and the poles attach the magnet to the soil and the energy lifts the magnet and the soil follows and it is attracted to the magnet

6 0

4 years ago

Read 2 more answers

"One step in the manufacture of silicon wafers used in the microelectronics industry is the melt crystallization of silicon into

nevsk [136]

Answer:

fgfgfdgdg

Explanation:

gfdgfgfgd

7 0

3 years ago

John runs around a 126.5 m circular track 3.5 times in 4.17 minutes. What is his average speed?

sdas [7]

Average speed = distance traveled / time

average speed = (126.5 m * 3.5 laps) / (4.17 min)

= 106.2 m/min

6 0

3 years ago

When a 25-kg crate is pushed across a frictionless horizontal floor with a force of 200 N, directed 20 below the horizontal, th

Fofino [41]

Answer:

Option E is correct 310N

Explanation:

Given that the force used to push the crate is F = 200N

The force directed 20° below the horizontal

Mass of crate is m = 25kg

Weight of the crate can be determine using

W = mg

g is gravitational constant =9.8m/s²

W = 25×9.8

W = 245 N

Check attachment. For free body diagram and better understanding

Using newton second law along the vertical axis since we want to find the normal force

ΣFy = m•ay

ay = 0, since the body is not moving in the vertical or y direction

N—W—F•Sin20 = 0

N = W+F•Sin20

N = 245+ 200Sin20

N = 245 + 68.4

N = 313.4 N

The normal force is approximately 310 N to the nearest ten

3 0

3 years ago