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3 years ago

How much electrical energy is used by a 400 W toaster that is operating for 5

Physics

1 answer:

andrew11 [14]3 years ago

8 0

Answer:

The answer is C. 120,000 J.

Explanation:

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A bowling ball has a mass of 5 kg. What happens to its momentum when the speed increases from 1 m/s to 2 m/s?

Alona [7]

<span>The initial momentum is 5 kg m/s and the final momentum is 10 kg m/s

'cause P = m*v, when we increase either m or v, P also increases by the same expression,

P = 5 * 2 = 10

So, option D is your answer!!

Hope this helps!

</span>

5 0

3 years ago

Read 2 more answers

Two trains leave the station at the same time, one heading east and the other west. the eastbound train travels at 85 miles per

kakasveta [241]

<span>Since the trains area headed in completely opposite directions, the rate at which they gain distance from each other is simply equal to the sum of the magnitudes of their velocities, in this case 85 + 75 = 160 miles per hour. Therefore, the amount of time it will take for them to be 352 miles apart is 352/160 = 2.2 hours, or 2 hours and 12 minutes.</span>

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3 years ago

What is the wavelength of an FM radio

AleksandrR [38]

V = 3.0 x 10⁸ m/s (This is the same for all types of electromagnetic waves)

f = 88.6 MHz = 8.86 x 10⁷ Hz

λ = ?

V = fλ

λ = V/f = (3 x 10⁸)/(8.86 x 10⁷)

= 3.4 m [Ans]

Hope this helps!

4 0

3 years ago

You are running at a speed of 10km/h and hit a patch of mud. Two seconds later you speed is 8km/h. What is your acceleration in

Vlad1618 [11]

Answer:

$0.28 m/s^2$

Explanation:

Acceleration is given by

$a=\frac{v-u}{t}$

where

u is the initial velocity

v is the final velocity

t is the time interval

In this problem:

$u = 10 km/h \cdot \frac{1000 m/km}{3600 s/h}=2.78 m/s$ is the initial velocity

$v = 8 km/h \cdot \frac{1000 m/km}{3600 s/h}= 2.22 m/s$ is the final velocity

t = 2 s is the time

Substituting, we find the acceleration:

$a=\frac{2.78-2.22}{2}=0.28 m/s^2$

5 0

4 years ago

For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red

barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

$z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1$

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

$z=\sqrt{\frac{c+v}{c-v}}-1$

- A red dwarf moving away from Earth at 39.1 km/s :

$z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}$

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

$z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}$

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

$z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}$

- A blue dwarf moving away from Earth at 25.9 km/s $z=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}$

- A red dwarf moving transversely at 14.1 km/s

$z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}$

6 0

4 years ago