Take left to be the negative direction, and right to be positive. That means the forces on the squirrel would be -2N and 3N.
Add all the forces to find the net force on the squirrel. -2N+3N=1N
Because the positive direction is to the right, the net force of 1N is directed to the right.
Answer:
∆p=(m2v)kg.m/s
Explanation:
∆p=mv where v=2v. hence ∆p=m2v
From newtons second law of motion,
F=ma hence,
F=20N
m=5kg so,
20=5×a
a=4m/s^2
Answer:
a) t = 4.5 s
, b) x = 81 m
Explanation:
a) For this problem we will use kinematic relationships
For the car
x = v₀ t + ½ a₁ t²
Since the car kicks from rest, the initial speed is zero
x = ½ a₁ t²
For the bus
v₂ = x / t
x = v₂ t
At the point where they are located it has the same position, so we can match the equation
½ a₁1 t² = v₂ t
½ a₁ t = v₂
t = 2 v₂ / a₁
Let's calculate
t = 2 18 /8.0
t = 4.5 s
b) to find the position
x = v₂ t
x = 18 4.5
x = 81 m
