Answer: A glass object receives a positive charge of +3 nC by rubbing it with a silk cloth. In the rubbing process electrons been removed from it.
Explanation:
It is known that for every atom the protons and neutrons reside in the nucleus of the atom. Whereas electrons move outside the nucleus of an atom. As a result, electrons are able to transfer more easily from one substance to another as compared to the protons.
This is because protons are tightly held by the nucleus of an atom. Whereas electrons are mobile in nature and hence, they can easily move.
Therefore, positive charge on the glass develops due to the removal of electrons from it.
thus, we can conclude that in the given process electrons been removed from the glass object.
Force = mass x acceleration
Mass is given to be 250kg
Acceleration is given to be 5m/s^2
Force = 250kg x 5m/s^2 = 1,250 kgm/s^2 = 1,250 Newtons
Answer:
2 m = E / c^2 where m is mass of electron
E = h v where v is the frequency ( nu) of the incident photon
E = h c / y where y is the incident wavelength (lambda)
2 m = h / (c y)
y = h / (2 m c) wavelength required
y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8) m
y = 3.31 / 27.3 E-11 m
y = 1.21 E -12 m = .0121 Angstrom units
Answer
given,
mass of the rod = 1.50 Kg
length of rod = 0.85 m
rotational velocity = 5060 rev/min
now calculating the rotational inertia of the system.
where L is the length of road, we will take whole length of rod because mass is at the end of it.
I = 1.084 kg.m²
hence, the rotational inertia the system is equal to I = 1.084 kg.m²
A jet fighter flies from the airbase A 300 km East to the point M. Then 350 km at 30° West of North.
It means : at 60° North of West. So the distance from the final point to the line AM is :
350 · cos 60° = 350 · 0.866 = 303.1 km
Let`s assume that there is a line N on AM.
AN = 125 km and NM = 175 km.
And finally jet fighter flies 150 km North to arrive at airbase B.
NB = 303.1 + 150 = 453.1 km
Then we can use the Pythagorean theorem.
d ( AB ) = √(453.1² + 125²) = √(205,299.61 + 15,625) = 470 km
Also foe a direction: cos α = 125 / 470 = 0.266
α = cos^(-1) 0.266 = 74.6°
90° - 74.6° = 15.4°
Answer: The distance between the airbase A and B is 470 km.
Direction is : 15.4° East from the North.
