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anastassius [24]
3 years ago
13

A small solid sphere and a small thin hoop are rolling along a horizontal surface with the same translational speed when they en

counter a 20 ∘ rising slope.. . If these two objects roll up the slope without slipping, which will rise farther up the slope?. The sphere.. The hoop.. Both the same.. More information about the objects' mass and diameter is needed..
Physics
1 answer:
torisob [31]3 years ago
3 0
This situation has a basis such that the solid sphere and the hoop has the same mass. The analysis could be made<span> backwards . The ball will decelerate fastest, so not roll as high. The sphere will accelerate faster, but this also means it decelerates faster on the way up. Hence the answer is the hoop if the masses are equal </span>
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Which law of motion accounts for the following statement? "A ball hit by a man travels faster than one hit by a boy."
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A ball hit by a man is stronger than a ball hit by a man because the man uses more force when hitting the ball than the boy does.

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A 10-cm long solenoid has 100 turns and a radius of 5 cm. If it carries a current of 2 A, What is the magnetic field B inside th
OLga [1]

Hi there!

We can use Ampère's Law:

\oint B \cdot dl = \mu_0 i_{encl}

B = Magnetic field strength (B)
dl = differential length element (m)
μ₀ = Permeability of free space (T/Am)

Since this is a closed-loop integral, we must integrate over a closed loop. We can integrate over a rectangular-enclosed area of the rim of the solenoid - ABCD - where AD and BC are perpendicular to the solenoid.

Thus, the magnetic field is equivalent to:
\oint B \cdot dl = \int\limits^A_B {B} \, dl  + \int\limits^B_C {B} \, dl   + \int\limits^C_D {B} \, dl   + \int\limits^D_A {B} \, dl

Since AD and BC are perpendicular, and since:
\oint B \cdot dl = B \cdot L = BLcos\phi

BLcos(90) = 0

If perpendicular to the field, the equation equals 0.

Additionally, since AB is outside of the solenoid, there is no magnetic field present, so B = 0. The only integral we integrate now is:
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Which is horizontal and inside the solenoid. Let the distance between C and D be 'L', and the enclosed current is equivalent to the number of loops multiplied by the current:

B L = \mu_0 Ni

N = # of loops per length multiplied by the length, so:
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Plug in the given values and solve. Remember to convert # of loops to # of loops per unit length.

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6 0
2 years ago
8. Two positive charges (+8.0 mC and +2.0 mC) are separated by 300 m. A third charge is placed at distance r from the +8.0 mC ch
muminat

Answer:

0.20 km

Explanation:

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This can be calculated by using the following formula

As we know that

\frac{k_q_1}{r^2} = \frac{k_q_1}{(300 - r)^2}

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Now

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4 0
3 years ago
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