Given:
u= 0.91 m/s
a=0.31m/s∧2
s= 0.61 m
s = ut +1/2(at∧2)
where s is the displacement of the object
u is the initial velocity
t is the time
a is the acceleration
Substituting the values
0.61=0.91×t +(0.31 ×t∧2)/2
0.61=0.91 t + 0.155 t∧2
t=0.61 secs
Consider the equation
<u>v=u +at
</u>
where v is the initial velocity
u is the initial velocity
a is the acceleration
t is the time
Substituting the values we get
v= 0.91 +(0.31×0.61)
v= 1.099 m/s
Answer:
Angular momentum is conserved if there are no external forces
P1 = P2
I1 ω1 = I2 ω2
ω2 / ω1 = I1 / I2
If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.
Answer:
12N
Explanation:
given- mass, acelation
Fnet=ma= .16kg*75m/s2
Fnet=12 N only force no friction given.
Answer:
Maximum horizontal distance covered by both the stones will be same because the speed at which both the stones are thrown is same.
However, stone that is thrown upward will spend more time in the air as compared to the stone that is thrown downward because of the projectile and vertical component of the velocity.
Answer: the answer is 23voltage
Explanation: because the voltage and time put together is 23