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lorasvet [3.4K]
3 years ago
10

What is the term for the force exerted by an object when it is pushed by another object?

Physics
2 answers:
Stella [2.4K]3 years ago
8 0

reaction force

 

action force

 

collision force

 

net force

kolezko [41]3 years ago
5 0
Action-reaction pairs.

This is in reference to Newton’s second law of motion.
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Calculate the time period of simple pendulum whose length is 98.2cm
alekssr [168]

The time period resulting in oscillations will be 1.986 seconds.

<h3>What is the period of oscillation?</h3>

The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.

The time period of the oscillation is;

\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \  \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec

Hence the time period resulting oscillations will be 1.986 seconds.

To learn more about the time period of oscillation refer to the link;

brainly.com/question/20070798

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2 years ago
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The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
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A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

Substituting these values, we find the power emitted by radiation:
P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW
So, the correct answer is D.
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<span>4.0 m/s2


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