3 years ago

What is the term for the force exerted by an object when it is pushed by another object?

Physics

2 answers:

Stella [2.4K]3 years ago

8 0

reaction force

action force

collision force

net force

kolezko [41]3 years ago

5 0

Action-reaction pairs.

This is in reference to Newton’s second law of motion.

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Calculate the time period of simple pendulum whose length is 98.2cm

alekssr [168]

The time period resulting in oscillations will be 1.986 seconds.

<h3>What is the period of oscillation?</h3>

The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.

The time period of the oscillation is;

$\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \ \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec$

Hence the time period resulting oscillations will be 1.986 seconds.

To learn more about the time period of oscillation refer to the link;

brainly.com/question/20070798

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2 years ago

A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt

Yuri [45]

The total power emitted by an object via radiation is:
$P=A\epsilon \sigma T^4$
where:
A is the surface of the object (in our problem, $A=1.25 m^2$
$\epsilon$ is the emissivity of the object (in our problem, $\epsilon=1$ )
$\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4)$ is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is $T=100^{\circ} C=373 K$

Substituting these values, we find the power emitted by radiation:
$P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW$
So, the correct answer is D.

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3 years ago

temperatura en la ciudad de la página madrugada y 2 grados bajo cero y a las 8 de la mañana sube a 6 grados y luego ya a las 10

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Answer:

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Explanation:

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3 years ago

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Can you hear it? In the cartoon space rocket, why do you think you would not be able to hear the whoosh of the rocket engine in

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