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eduard
3 years ago
11

A toy car was used in an investigation about unbalanced forces. During which of the following scenarios was the car not experien

cing an unbalanced force? *
20 points
1.The toy car speeds up as it rolls down a ramp.
2.The toy car travels forward at a constant speed.
3.The toy car slows down as it rolls up a hill.
4.The toy car changes direction at a constant speed.
Physics
2 answers:
lozanna [386]3 years ago
7 0
Number 2, the question asked which car was not experiencing a unbalanced force. number 2 says the car is traveling at a constant speed signifying that nothing was in the cars way allowing it to travel with ease
Firlakuza [10]3 years ago
4 0

Answer:

Number 2

it is using Newton’s first law.

also known as the law of inertia

look that last word up

Explanation:

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True or false cold air can hold more moisture than warm air
agasfer [191]
It is true
I hope this helps
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3 years ago
1 point<br> You throw a ball up in the air with a velocity of 30 m/s. How high does it<br> go?
choli [55]

Answer:

Explanation:

2as=vf^2-Vi^2

vf=30 m/s

vi= 0 m/s

a=g=9.8 m/s^2

s=vf^2-Vi^2/2a

s=(30)²-(0)²/2*9.8

s=900-0/19.6

s=45.9=46 m

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2 years ago
Recording the location of a star requires a measurement of:
Scorpion4ik [409]

Answer:

It requires a measurement of altitude azimuth time.

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7 0
3 years ago
II. IDENTIFY THE TYPE OF FORCE
uysha [10]

Answer:

Explanation:

1. Frictional force is responsible for running of car and buses on roads.

2.Gravitational force exists between astronauts in space.

3. Magnetic for is responsible to attract the iron objects using a magnet

4.Electrostatic force is responsible for fiber to stick on the skin.This force occurs due to the presence of charge.

5.When a person is pushing a trolley then object experience a normal reaction from ground.

6.Gravitational force makes the planet to move in their orbits.

4 0
3 years ago
A spring with spring constant of 34 N/m is stretched 0.12 m from its equilibrium position. How much work must be done to stretch
Nesterboy [21]

Answer:0.253Joules

Explanation:

First, we will calculate the force required to stretch the string. According to Hooke's law, the force applied to an elastic material or string is directly proportional to its extension.

F = ke where;

F is the force

k is spring constant = 34N/m

e is the extension = 0.12m

F = 34× 0.12 = 4.08N

To get work done,

Work is said to be done if the force applied to an object cause the body to move a distance from its initial position.

Work done = Force × Distance

Since F = 4.08m, distance = 0.062m

Work done = 4.08 × 0.062

Work done = 0.253Joules

Therefore, work done to stretch the string to an additional 0.062 m distance is 0.253Joules

8 0
3 years ago
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