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3 years ago

Two equal forces result. explain why the box moves even thought the forces are equal and opposite

1 answer:

4 0

The answer might be because of kinetic energy is still there and it got transferred, but it's hard to tell, I'd need more info:/

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Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is mo

vova2212 [387]

Answer: The answer is A.

Explanation:

Suppose you are in an elevator. As the elevator starts upward, its speed will increase. During this time when the elevator is moving upward with increasing speed, your weight will be greater than your normal weight at rest.

5 0

3 years ago

What is the gravitational potential energy of a 0.1 kg apple sitting on top of a 12.5 m flagpole? Note: GPE= mgh. m= mass, g= ac

Pachacha [2.7K]

GPE= mgh = 0.1 kg * 9.8 m/s^2 * 12.5m = 12.25 J

6 0

3 years ago

As a box is pushed 30 meters across a horizontal floor by a constant horizontal force of 25 newtons, the kinetic energy of the b

irakobra [83]

Answer:

1,050 Joules

Explanation:

Step 1: work done in moving the box 30 meters

work done = force X distance

= 25N X 30 = 750 Joules

Step 2: calculate total internal energy

Total internal energy = work done + kinetic energy

= 750 Joules + 300 Joules

= 1,050 Joules = 1.05 KJ

5 0

3 years ago

What is the center of our solar system?

Yakvenalex [24]

The sun is the centre of our solar system

8 0

3 years ago

Hey guys can you help me solve this problem "how long will it take a car travelling 30m/s to come to stop ifs its acceleration i

salantis [7]

Answer:

10 seconds.

Explanation:

We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time t:

$\displaystyle v_f = v_i + at$

The initial velocit is 30 m/s, the final velocity is 0 m/s (as we stopped), and the acceleration is -3 m/s².

Substitute and solve for t:

$\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\ t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}$

Hence, it will take the car 10 seconds to come to a stop.

7 0

2 years ago