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lozanna [386]
3 years ago
11

How many significant figures are in this number? 3 x 10^6

Chemistry
1 answer:
tankabanditka [31]3 years ago
8 0
There is 1 sigfig in that number and the sigfig is 3
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When sufficient quantity of heat has been added to reach the boiling point of a solution, what happens to any additional heat ad
Daniel [21]

Answer:

d) additional heat alters the vicosity and the surface tension of the liquid which raises the vapor pressure and increases the boiling point which is why you must continually heat the solution

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3 years ago
Why are the bacterial endospores placed on the paper strip and not directly in the fermentation broth?
Artyom0805 [142]
The bacterial endospores are microorganisms formed due to nutrient deprivation. These are placed first on a paper strip and not directly in the fermentation broth because these microorganisms are very resistance, thus, they need to adjust to the environment first before being acclimated to it. 
6 0
4 years ago
1. Write chemical reaction of burning of magnesium
shtirl [24]

Answer:

1.Mg+O2.......MgO2

Explanation:

2.Very reactive towards halogens and reacts with water at room temperature. 3, Magnesium oxide is a simple basic oxide. 4.It will react with water to form magnesium hydroxide which is a base turning red litmus to blue 5.should be white. hope it helped. I help people although when I post a question it is left unanswered and then gets answers after two days when I don't really need it

4 0
3 years ago
In order to boil, a liquid's vapor pressure must be greater than the pressure of the atmosphere.
hjlf

The anwser is false.

5 0
3 years ago
Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
3 years ago
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