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olchik [2.2K]
3 years ago
10

Happy is to joy as mourn is to ____________​

Chemistry
1 answer:
Tasya [4]3 years ago
8 0
Grief.

To mourn is to feel great sadness or regret for something.

Grief, lament, weep, shed tears, deplore, bewail, bemoan, rue, and regret.
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A chemist weighs out 0.0865 g of sulfurous acid, H2SO3, which is a diprotic acid into a 250. mL of volumetric flask and dilutes
kobusy [5.1K]

<u>Answer:</u> The volume of NaOH needed to add is 12.35 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of sulfurous acid = 0.0865 g

Molar mass of sulfurous acid = 82.079 g/mol

Volume of solution = 250 mL

Putting values in above equation, we get:

\text{Molarity of sulfurous acid}=\frac{0.0865\times 1000}{82.079\times 250}\\\\\text{Molarity of sulfurous acid}=0.0042M

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.0042M\\V_1=250mL\\n_2=1\\M_2=0.1700M\\V_2=?mL

Putting values in above equation, we get:

2\times 0.0042\times 250=1\times 0.1700\times V_2\\\\V_2=\frac{2\times 0.0042\times 250}{1\times 0.1700}=12.35mL

Hence, the volume of NaOH needed to add is 12.35 mL

3 0
4 years ago
What types of star can explode in a supernova
horrorfan [7]
For a star to explode as a Type II supernova, it must be at several times more massive than the sun<span> (estimates run from eight to 15 solar masses). Like </span>the sun<span>, it will eventually run out of hydrogen and then helium fuel at its core. However, it will have enough mass and pressure to fuse carbon.
i had to right an essay on this stuff.</span>
4 0
3 years ago
2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C.ten temperature of the water increases to 23.5 C. How muc
Dominik [7]

Answer:

2.6 kJ  

Explanation:

The formula for the amount of heat (q) absorbed by the water is

q = mCΔT

1. Calculate ΔT

ΔT = 23.5 °C - 22.1 °C = 1.4 °C

2. Calculate q

q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ

3 0
4 years ago
What will be the ph of a buffer solution containing an acid of pka7. 5, with an acid concentration exactly one fourth of that of
Lilit [14]

The pH of a buffer solution containing acid of pKa 7.5 will be 8.1.

The pH of a solution indicates its acidity or basicity. A pH below 7 is acidic, while pH above 7 is basic. 7 is considered as the neutral value.

A buffer is a solution that has the ability to resist the change in pH when an acid or a base is added to it. The natural example of buffer is blood.

According to the question, pKa of acid = 7.5

If concentration of base is x then, concentration of acid will be x/4.

According to the Henderson–Hasselbalch equation,

pH = pKa + log [A⁻] / [HA]

pH = 7.5 + log [\frac{x}{x/4}]

pH = 7.5 + log 4 ⇒ 7.5 + 0.602

pH = 8.1

To know more about buffer, here

brainly.com/question/22821585

#SPJ4

5 0
2 years ago
Diffusion of nonpolar molecules would not be affected by
wariber [46]
 +molecule size +steepness of the concentration gradient +temperature + steepness of the electric gradient +steepness
7 0
3 years ago
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